What is the electron configuration for lithium iodide?

Answer 1

..

[Li]+ [:I:]- (put the last 2 pairs above and below the "I" this wont let me)

..

Answer 2

The electron configuration for lithium is 1s^2 2s^1 and for iodine is 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^5. In lithium iodide (LiI), lithium will lose its 2s electron to iodine, forming Li+ and I- ions. So, the final electron configuration for lithium iodide is [He] for Li+ and [Kr] for I-.