What is the electron configuration of Ag ion?

Answer 1

Electron configurations:

Ag metal is: [Kr] 4d10, 5s1 ,

so Ag+ ion is in shorthand: [Kr] 4d10, 5s0 or [Kr] 4d10

and in full notaion:

[1s2, 2s2 2p6, 3s2 3p6 3d10, 4s2 4p6] 4d10

Answer 2

Ag, or silver, has the atomic number 47. Its orbital notation is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1 4d10.

Answer 3

Long-hand version: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^9 Short-hand version: [Kr] 5s^2 4d^9 Note: The "^" symbol means the the following number is in the form of a superscript.

Answer 4

There is one valence electron for silver, so there is one dot

This is not true for all compounds of silver and all forms of silver.

Consider silver fluroide.

Answer 5

Using classical notation: 2.8.8.18.11

And quantum notation: [Kr]5s14d10

Answer 6

The electron configuration of Ag ion (Silver ion) is [Kr] 4d^10. This is because the Ag ion has lost one electron from the neutral Ag atom, which has an electron configuration of [Kr] 4d^10 5s^1.

Answer 7

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d9