1s^22s^2
Or
[He]2s^2
First, look how many electrons are present. This is indicated by the atomic number located in the Periodic Table above the specific element. Secondly, use the list of orbitals to remember the order:
1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s.
S=2 electrons
P=6 electrons
D=10 electrons
ex: The element Boron (B)= 1s^2 2s^2 2p^1. You are looking at the (^2, ^2, ^1). Which adds to five, the total number of electrons in a neutral Bromine element.
(There is an f, but it is rarely used)
Hope that helps!
Be, atomic number 4, electron configuration 1s2, 2s2 , so
Be2+ ion is (shorthanded) 1s2, 2s0, or simplified: 1s2
The atomic number of beryllium (Be) is 4, which means all Be atoms contain 4 protons. A neutral Be atom also contains 4 electrons. However, a Be2+ cation has lost two electrons.
Neutral Be atom: 1s2 2s2
Be2+ cation: 1s2
Be is the third element in the periodic table and is written as (2,1)
Electron configuration of beryllium: 1s22s2
[Kr]4d105s25p6
The Fe2 plus electron configuration is 1s2 2s2 2p6 3s2 3p6 3d6.
The electronic configuration of tin is: [Kr]D10.5s2.5p2.The electronic configuration of chromium(2+) is correct.
There is no element such as 12M. Assuming that you mean 12Mg, the electron configuration is 2, 8, 2.
Rhodium (Rh) forms a 3 plus ion that has the electron configuration Kr4d6. Rhodium has oxidation states of 2,3 and 4, so it can loan out 2, 3 or 4 electrons depending on the circumstances of a chemical reaction.
Cobalt electron configuration is [Ar]3d7.4s2.Cobalt(2+) electron configuration is [Ar]3d7.
Cobalt(II) electron configuration is [Ar]3d7.
[Kr]4d105s25p6
The electron configuration of copper(II) is [Ar] 3d9 . Copper is [Ar] 3d10 4s1
The Fe2 plus electron configuration is 1s2 2s2 2p6 3s2 3p6 3d6.
The electron configuration of Cu2+ is [Ar]3d94s0.
The electronic configuration of tin is: [Kr]D10.5s2.5p2.The electronic configuration of chromium(2+) is correct.
The electron configuration for a magnesium cation Mg2 plus is 1s2.2s2.2p6.
The electron configuration of selenium for a 2- ion is [Kr]4s2.3d10.4p6.
There is no element such as 12M. Assuming that you mean 12Mg, the electron configuration is 2, 8, 2.
It has 39 electrons and ends in a d orbital. Now finish your homework :)
no. it doesn't