The electron configuration of sodium is: [Ne]3s1.
Na is an s-block element, in group 1, period 3 and it has 11 electrons. Thus, the configuration is
1s2 2s2 2p6 3s1
selenium
An electron has a charge of -1. When a Sodium (Na) atom loses one electron, it loses a negative and becomes a stable Sodium ion with a charge of +1.
Na has one valence electron i.e. 1 electron in valence(last) shell.
Let us assume that we have Sodium (Na), it has the ground state electron configuration of: [Ne]3S1. The ANION is negative, and thereby has more electrons, the Na anion(Na.) would have the following electron configuration: [Ne]3S2. The CATION(which is a positive ion) of Na(Na+) would have [Ne] as it electron configuration(as it loses an electron and becomes "equal" to Neon)
Sodium donates one electron from it's valance shell and becomes the cation, Na + Having a 1 + positive charge as it is short the one electron.
Electron configuration for an atom is the distribution of electrons on atomic orbitals.
selenium
A new ionic species - Na- (it does not exist) Perhaps you meant the loss of an electron? In this case, sodium readily loses an electron to form Na+.
2s.3s
Sodium loses one electron, therefore Na+ Chlorine gains an electron, therefore Cl-
In NaF, there exists Na+ and F- ions and with the electron configuration of [He]2s22p6 (for Na+) and [He]2s22p6 (for F-)
Neon has the same electron configuration as Na+ ion
remove an electron. Na = Na+ + e-
The electron-dot structure of sodium atom is 'Na-dot' or 'Na.' One dot is one valence electron.
In NaCl, there exists Na+ and Cl- ions and with the electron configuration of [He]2s22p6 (for Na+) and [Ne]3s23p6 (for Cl-)
The electron distribution differs between energy levels. In this case, levels one and four have 2 electrons, level 2 has eight, and level 3 has thirteen.
This sodium ion is denoted by: Na+