If you mean the compound formed from calcium and iodine, it is CaI2. It is named calcium iodide.
Calcium sulfide is CaS. This is the empirical formula as well.
The empirical formula for iodine is I2 and for rubidium is Rb.
Calcium = Ca Carbon = C oxide = O(2-) Calcium carbonate = CaCO3
The empirical formula for calcium and sulfur is CaS, which represents the simplest whole number ratio of atoms in the compound.
Calcium iodide is CaI2.
Calcium sulfide is CaS. This is the empirical formula as well.
The empirical formula for iodine is I2 and for rubidium is Rb.
Calcium = Ca Carbon = C oxide = O(2-) Calcium carbonate = CaCO3
The chemical formula for Calcium oxide is CaO. A single calcium atom bonds with a single oxygen atom to make this compound, and a link can be found below for more information.CaO
Ca3P2 or Ca3(PO4)2 See related question below for more details on how to find empirical formulas.
The empirical formula for calcium and sulfur is CaS, which represents the simplest whole number ratio of atoms in the compound.
Calcium iodide is CaI2.
Chlorine and iodine are both elements that form diatomic molecules (molecules that consist of two atoms). One atom of chlorine is symbolised by Cl; however, single atoms of chlorine do not exist unattached to other atoms. One molecule of chlorine is Cl2. The situation is the somewhat similar for iodine, and a molecule of iodine is I2. Please see the links.
Calcium Iodide, CaI2, contains calcium, Ca and iodine, I.
The empirical formula for calcium bromide dihydrate is CaBr2·2H2O. This means there are two bromide (Br) ions for every calcium (Ca) ion, and two water (H2O) molecules per unit.
The empirical formula would be CaBr2 since it contains a ratio of 1 calcium to 2 bromine atoms.
CaI2 . This is calcium iodide. Recall, Ca2+ and I-. Therefore, two iodine atoms are needed for every 1 calcium. The suffix also changes to -ide; this happens for all halogens.