you divide by 2 since all can be divisible by 2
so
H2S2O8 becomes HSO4
H2S2O7 is the chemical formula for disulfuric acid. This compound is analogous to an acid anhydride and is typically found in nature as a major component in fuming sulfuric acid.
H2SO4 is an empirical formula.
Empirical formula is the simplest formula that shows the simplest ratio of the different types of atoms in it. tartaric acid is made up of C4H6O6, which can be further simplified to be C2H3O3.
PO2
Empirical formula is a useless notion; important is the molecular formula.
This is an empirical formula - a formula without indication about the structure of the molecule.
CH2O is not only the empirical but also the molecular formula for formaldehye. It is also the empirical but not the molecular formula for hydroxyacetaldehyde, acetic acid, methyl formate, 1,3-dihydroxyacetone, and many other compounds.
The empirical formula of acetic acid is CH3COOH.
Empirical formula is the simplest formula that shows the simplest ratio of the different types of atoms in it. tartaric acid is made up of C4H6O6, which can be further simplified to be C2H3O3.
The formula for nitric acid is HNO3.
The empirical formula is similar.
Yes, it is possible for an empirical formula to be the same as the molecular formula. For example, Lactic acid's molecular formula is C3H6O3, which would make its empirical formula CH2O.
PO2
Empirical formula is a useless notion; important is the molecular formula.
This is an empirical formula - a formula without indication about the structure of the molecule.
CH2O is not only the empirical but also the molecular formula for formaldehye. It is also the empirical but not the molecular formula for hydroxyacetaldehyde, acetic acid, methyl formate, 1,3-dihydroxyacetone, and many other compounds.
C2H4O2 normally written as CH3COOH to show the presence of the carboxyic acid group
It is an empirical formula.
Well you know that Butanoic Acid's Molecular formula is C3H7COOH, and Empirical formula is a compound showig the simplest ratio of numbers of atoms of each element in the compound. Now the question is, can you simply C3H7COOH ? Nope! Then the Empirical formula is also C3H7COOH