The enthalpy of neutralization of a strong acid against a strong base is always constant (13.7 kcal or 57 kJ mole-1). It is because in dilute solutions all strong acids and bases ionize completely and thus the heat of neutralization in such cases is actually the heat of formation of water from H+ and OH- ions, i.e.,
H+ + OH- ---> H2O; ΔH = -13.7 kcal
Actually your question should sound "Why is the enthalpy change of neutralization of STRONG ACID and STRONG BASE equal to -57.2kJmol-1?". This is because when STRONG ACID and STRONG BASE react and neutralization process occur, a complete ionization will occur. Therefore, they will have almost the same value of enthalpies and can be assummed to be -57.2kJmol-1. As per mentioned that if your question sounds "Why is the enthalpy change of neutralization of STRONG ACID and STRONG BASE equal to -57.2kJmol-1?", then my explaination above will be helpful. However, if it doesn't sound like mine and you insisted with your question titled "Why is the enthalpy change of neutralization equal to -57.2kJmol-1", then my answer is that they didn't equal to -57.2kJmol-1 and it varies from the list of reactants. 1. STRONG acid + STRONG base = -57.2 2. WEAK acid + WEAK base = less than 57.3kJmol-1 3. WEAK acid + STRONG base = more negative than -57.3kJmol-1 Wish that it is useful as your reference. Prompt me if I am wrong.
The enthalpy change when hydrochloric acid reacts with magnesium is exothermic, meaning it releases heat energy.
The enthalpy change when magnesium reacts with hydrochloric acid is exothermic, meaning it releases heat energy.
Enthalpy change of neutralisation is defined as the enthalpy change of a reaction where one mole of hydrogen ions reacts with one mole of hydroxide ions to form one mole of water under standard conditions of 1 atm, 298K (25 degree Celsius) and in the solutions containing 1 mol per dm3.
use the formula for enthalpy change for the reaction of an acid and base to produce 1mol of water. dH=mc(dT)/n where H = enthalpy m = mass of system c = specific heat capacity of system T = temperature of system n = number of moles reacted
yea
Actually your question should sound "Why is the enthalpy change of neutralization of STRONG ACID and STRONG BASE equal to -57.2kJmol-1?". This is because when STRONG ACID and STRONG BASE react and neutralization process occur, a complete ionization will occur. Therefore, they will have almost the same value of enthalpies and can be assummed to be -57.2kJmol-1. As per mentioned that if your question sounds "Why is the enthalpy change of neutralization of STRONG ACID and STRONG BASE equal to -57.2kJmol-1?", then my explaination above will be helpful. However, if it doesn't sound like mine and you insisted with your question titled "Why is the enthalpy change of neutralization equal to -57.2kJmol-1", then my answer is that they didn't equal to -57.2kJmol-1 and it varies from the list of reactants. 1. STRONG acid + STRONG base = -57.2 2. WEAK acid + WEAK base = less than 57.3kJmol-1 3. WEAK acid + STRONG base = more negative than -57.3kJmol-1 Wish that it is useful as your reference. Prompt me if I am wrong.
you create a neutral solution -------------------------------------------------------------------------------------------- Well it depends actually it doesn't always create a neutral solution. Here's the order: Strong Alkali + Strong Acid = Neutralisation (water + salt) Strong Alkali + Weak Acid = Weak Alkali Weak Alkali + Weak Acid = Neutralisation ( water + salt) Weak Alkali + Strong Acid = Weak Acid Strong Alkali + Strong Acid = Neutralisation (water + salt) Hope it helps! :)
The enthalpy change when hydrochloric acid reacts with magnesium is exothermic, meaning it releases heat energy.
The enthalpy change when magnesium reacts with hydrochloric acid is exothermic, meaning it releases heat energy.
pH7,Which It Water.
Enthalpy of solution of oxalic, succinic, adipic, maleic, malic, tartaric, and citric acids, oxalic acid dihydrate, and citric acid monohydrate in water at 298.15 K
It depends you can sometimes get an alkaline salt.if you use a strong acid and a weak base during neutralisation you will get an acidic salt (eg. Ammonia chloride. Made from hydrochloric acid and ammonia) However, if you use a weak acid and a strong base during neutralisation you will get an alkaline salt (eg. Sodium ethanoate. Made from sodium hydroxide and ethanoic acid)
Enthalpy change of neutralisation is defined as the enthalpy change of a reaction where one mole of hydrogen ions reacts with one mole of hydroxide ions to form one mole of water under standard conditions of 1 atm, 298K (25 degree Celsius) and in the solutions containing 1 mol per dm3.
The standard enthalpy change of neutralization between hydrofluoric acid and sodium hydroxide is more negative because hydrofluoric acid is a weak acid, so it undergoes complete ionization during neutralization. This means it releases more heat compared to a strong acid. Additionally, the reaction between hydrofluoric acid and sodium hydroxide forms water and a salt, which are both strong electrolytes, leading to a more exothermic reaction.
no if the acid is strong and the base is weak then the salt will be slightly acidic. sources: chemistry teacher :)
No, changing the concentration of an acid does not affect the temperature at neutralisation. The temperature change during neutralisation is determined by the amount of heat released or absorbed during the reaction, which is dependent on the specific acid and base involved, not their concentrations.