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The enthalpy of neutralization of a strong acid against a strong base is always constant (13.7 kcal or 57 kJ mole-1). It is because in dilute solutions all strong acids and bases ionize completely and thus the heat of neutralization in such cases is actually the heat of formation of water from H+ and OH- ions, i.e.,
H+ + OH- ---> H2O; ΔH = -13.7 kcal
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What is the effect of acid strength on the enthalpy of neutralization?
There is no connection between enthalpy of neutralisation and whether the acid is weak or strong. The enthalpy of the reaction depends on ALL reactions and changes that happen, not just the one involving the hydrogen ion.
Why is the enthalpy of neutralization different between strong and weak acids?
There is no connection between enthalpy of neutralisation and whether the acid is weak or strong. The enthalpy of the reaction depends on ALL reactions and changes that happen, not just the one involving the hydrogen ion.
Why is the enthalpy change of neutralisation equal to -57.2kJ mol-1?
Actually your question should sound "Why is the enthalpy change of neutralization of STRONG ACID and STRONG BASE equal to -57.2kJmol-1?". This is because when STRONG ACID and STRONG BASE react and neutralization process occur, a complete ionization will occur. Therefore, they will have almost the same value of enthalpies and can be assummed to be -57.2kJmol-1. As per mentioned that if your question sounds "Why is the enthalpy change of neutralization of STRONG ACID and STRONG BASE equal to -57.2kJmol-1?", then my explaination above will be helpful. However, if it doesn't sound like mine and you insisted with your question titled "Why is the enthalpy change of neutralization equal to -57.2kJmol-1", then my answer is that they didn't equal to -57.2kJmol-1 and it varies from the list of reactants. 1. STRONG acid + STRONG base = -57.2 2. WEAK acid + WEAK base = less than 57.3kJmol-1 3. WEAK acid + STRONG base = more negative than -57.3kJmol-1 Wish that it is useful as your reference. Prompt me if I am wrong.
Why is the value of the enthalpy change of neutralization for a strong acid against a strong base constant?
Because the value changes at a constant degree
How do you calculate enthalpy of neutralisation?
use the formula for enthalpy change for the reaction of an acid and base to produce 1mol of water. dH=mc(dT)/n where H = enthalpy m = mass of system c = specific heat capacity of system T = temperature of system n = number of moles reacted
What is the effect of acid strength on the enthalpy of neutralization?
There is no connection between enthalpy of neutralisation and whether the acid is weak or strong. The enthalpy of the reaction depends on ALL reactions and changes that happen, not just the one involving the hydrogen ion.
Why is the enthalpy of neutralization different between strong and weak acids?
There is no connection between enthalpy of neutralisation and whether the acid is weak or strong. The enthalpy of the reaction depends on ALL reactions and changes that happen, not just the one involving the hydrogen ion.
Which equation do you use to calculate the enthalpy of neutralisation from an acid-base reaction?
yea
Why is the enthalpy change of neutralisation equal to -57.2kJ mol-1?
Actually your question should sound "Why is the enthalpy change of neutralization of STRONG ACID and STRONG BASE equal to -57.2kJmol-1?". This is because when STRONG ACID and STRONG BASE react and neutralization process occur, a complete ionization will occur. Therefore, they will have almost the same value of enthalpies and can be assummed to be -57.2kJmol-1. As per mentioned that if your question sounds "Why is the enthalpy change of neutralization of STRONG ACID and STRONG BASE equal to -57.2kJmol-1?", then my explaination above will be helpful. However, if it doesn't sound like mine and you insisted with your question titled "Why is the enthalpy change of neutralization equal to -57.2kJmol-1", then my answer is that they didn't equal to -57.2kJmol-1 and it varies from the list of reactants. 1. STRONG acid + STRONG base = -57.2 2. WEAK acid + WEAK base = less than 57.3kJmol-1 3. WEAK acid + STRONG base = more negative than -57.3kJmol-1 Wish that it is useful as your reference. Prompt me if I am wrong.
Why is the value of the enthalpy change of neutralization for a strong acid against a strong base constant?
Because the value changes at a constant degree
What is the reaction when you add acids and alkali's?
you create a neutral solution -------------------------------------------------------------------------------------------- Well it depends actually it doesn't always create a neutral solution. Here's the order: Strong Alkali + Strong Acid = Neutralisation (water + salt) Strong Alkali + Weak Acid = Weak Alkali Weak Alkali + Weak Acid = Neutralisation ( water + salt) Weak Alkali + Strong Acid = Weak Acid Strong Alkali + Strong Acid = Neutralisation (water + salt) Hope it helps! :)
How do you calculate enthalpy of neutralisation?
use the formula for enthalpy change for the reaction of an acid and base to produce 1mol of water. dH=mc(dT)/n where H = enthalpy m = mass of system c = specific heat capacity of system T = temperature of system n = number of moles reacted
What do you find out about the pH changes that take place when neutralisation occurs between a strong acid and a strong base?
pH7,Which It Water.
What is the heat of neutralisation of strong acid against strong base?
The heat of neutralization of a strong acid and a strong base is almost 57.03kJ/mol. It can also be written as 13.6kcal/mol. Further contact at saqibahmad81@yahoo.com
Is salt an acid?
It depends you can sometimes get an alkaline salt.if you use a strong acid and a weak base during neutralisation you will get an acidic salt (eg. Ammonia chloride. Made from hydrochloric acid and ammonia) However, if you use a weak acid and a strong base during neutralisation you will get an alkaline salt (eg. Sodium ethanoate. Made from sodium hydroxide and ethanoic acid)
Which type of reaction occurs when sulfuric acid and sodium hydroxide combine?
Neutralisation- Sodium hydroxide is a strong alkaline
What happens when an acid mixes with a alkali?
Because the acid is strong and the alkali has the same strengh, they both cancel each other out and the process called is. NEUTRALISATION!!!
