What is the entropy change for the third reaction below N2(g) plus O2(g) 2NO(g) and 8710H 180 kJ 2NO2(g) 2NO(g) plus O2(g) and 8710H 112 kJ N2(g) plus 2O2(g) 2NO2(g)?

Answer 1

68kj

Answer 2

The equation is: N2(g) + 2O2(g) -> 2NO2(g) Given enthalpy changes: 2NO(g) + O2(g) + 112 kJ -> 2NO2(g) N2(g) + O2(g) -> 2NO(g) + 180 kJ Using Hess's Law, we subtract the second equation from the sum of the first and third equations: 2NO2(g) - (2NO(g) + O2(g)) = 2NO2(g) - 2NO(g) - O2(g), resulting in the entropy change for the third reaction.