C + O ==> CO
Keq = [CO]/[C][O]
You get an increased yield of H2CO3, as the equilibrium shifts to the side with fewer moles.
In this reaction H3O+ is the conjugate acid. The original acid in this reaction is H3PO4
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
HX ---> H+ + X- Keq = [H+][X-]/[HX]
Water + Carbon dioxide Carbonic acidH2O + CO2 H2CO3 equilibrium
Keq = [H2O][CO] [H2][CO2]
h20 , hcn
You get an increased yield of H2CO3, as the equilibrium shifts to the side with fewer moles.
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
The products of neutralization reaction are water and a salt.
In this reaction H3O+ is the conjugate acid. The original acid in this reaction is H3PO4
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
HX ---> H+ + X- Keq = [H+][X-]/[HX]
Water + Carbon dioxide Carbonic acidH2O + CO2 H2CO3 equilibrium
The conditional constant= 1.8*1010
The chemical reaction is:2 Cs + 2 H2O = 2 CsOH + H2