More NO would form
More NO would form.
Adding NO to the system at equilibrium would increase the concentration of the NO product. According to Le Chatelier's principle, the system will counteract this change by producing more of the reactants, N2 and O2.
According to the balanced chemical equation, 3 liters of hydrogen is required to produce 2 liters of ammonia. So, for 12 liters of ammonia, you would need 18 liters of hydrogen. This is because the ratio of hydrogen to ammonia in the reaction is 3:2.
To determine the change in volume, you can use the ideal gas law equation: V2 = V1*(T2/T1). Substituting the values, the change in volume would be V2 - V1 = V1*(T2/T1) - V1. Just plug in the initial volume of 1.95 L, initial temperature of 250.0 K, and final temperature of 442.2 K to find the change in volume.
3H2(g) + N2(g) ---> 2NH3(g)
More No will be produced
More NO would form.
Adding NO to the system at equilibrium would increase the concentration of the NO product. According to Le Chatelier's principle, the system will counteract this change by producing more of the reactants, N2 and O2.
ΔS is positive and ΔG is negative at low temperatures only
According to the balanced chemical equation, 3 liters of hydrogen is required to produce 2 liters of ammonia. So, for 12 liters of ammonia, you would need 18 liters of hydrogen. This is because the ratio of hydrogen to ammonia in the reaction is 3:2.
To determine the change in volume, you can use the ideal gas law equation: V2 = V1*(T2/T1). Substituting the values, the change in volume would be V2 - V1 = V1*(T2/T1) - V1. Just plug in the initial volume of 1.95 L, initial temperature of 250.0 K, and final temperature of 442.2 K to find the change in volume.
3H2(g) + N2(g) ---> 2NH3(g)