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What is formal charge on H in ammonia?

In ammonia (NH3), the formal charge on hydrogen (H) is zero. This is because hydrogen is bonded to nitrogen, following the rule that hydrogen typically has a formal charge of zero when bonded to a more electronegative element like nitrogen.


What is the symbol for bicarbonate ion?

The chemical symbol for bicarbonate is HCO3-. This is because it has one carbon atom surrounded by three atoms and a hydrogen atom attached to one of them. The negative charge comes from one formal charge.


Formal charge for 2H-O-N-H?

2 Ho has got to be the opposite of h2o which means it is oxygen and water backwards !_!


Formula for zinc hydrogencarbonate?

Zinc is Zn; bicarbonate, also known as hydrogen carbonate, is HCO3; after taking into account the +2 charge of the Zn and the -1 charge of HCO3 we get: Zn(HCO3)2.


What is H plus HCO3?

I think you mean H+ + HCO3- --> H2CO3


What is the conjugate base for HCO3?

The conjugate base of HCO3- is CO32-. Conjugates always differ by one H+. A conjugate base has one fewer H+, while a conjugate acid has one more H+.


What is the formula for the compound nickel II carbonate?

Ni(HCO3)2 Ni has a +2 charge and bicarbonate aka hydrogen carbonate HCO3 has a -1 charge.


What is the difference between HCO3- and HCO3plus?

HCO3- is a anion (bicarbonate); HCO3+ don't exist.


What is the charge for bicarbonate ion?

The charge for the bicarbonate ion (HCO3-) is -1.


What is the formal charge of HoFo?

The formal charge of HoFo is 0. Ho has a formal charge of 0 because it is in group 8 of the periodic table, and Fo also has a formal charge of 0 because it is a neutral molecule. So put them together, and you get a big fat zero.


When HCO3- acts as a bronsted base what is formed?

When HCO3- acts as a Bronsted base, it accepts a proton (H+) to form H2CO3 (carbonic acid).


What is the chemical formula for plumbic hydroxide?

The formula for Plumbic carbonate is Pb(CO3)2 because the higher charge of lead has a charge of 4+ and CO3 has a charge of 2-, therefore the charges would diagonally switch and then be reduced to the simplest whole-number ratio.