Copper does not form +3 oxidation number. So there cant be a formula like that.
The formula for iron(III) sulfite is Fe2(SO3)3.
The chemical formula for the compound Copper (II) Sulfite Dihydrate is:CuSO3.2H2O
Fe2(SO3)3 Ferric sulfite or Iron III sulfite.Absorbs oxygen from the air to form iron III sulfate.
If it existed the formula would be Cu2O3
This does not exist. If it did, it would probably be something like "Copper(III) hydrogen sulfide"
The formula for iron(III) sulfite is Fe2(SO3)3.
The chemical formula for the compound Copper (II) Sulfite Dihydrate is:CuSO3.2H2O
The compound with the formula Cu2SO3 is called copper(I) sulfite. It is composed of copper ions with a +1 charge and sulfite ions with a -2 charge, resulting in the formula Cu2SO3.
The chemical formula for manganese(III) sulfite is Mn2(SO3)3.
These are the ions and their charges: Cu+2 SO3-2The charges have to add up to zero, so one +2 copper ion cancels out one -2 sulfite ion. Therefore, the formula is CuSO3.
The chemical formula for copper(II) hydrogen sulfite is Cu(HSO3)2.
Fe2(SO3)3 Ferric sulfite or Iron III sulfite.Absorbs oxygen from the air to form iron III sulfate.
If it existed the formula would be Cu2O3
This does not exist. If it did, it would probably be something like "Copper(III) hydrogen sulfide"
Iron (III) sulfite
Copper (III) doesn't exist; copper(II) arsenide is Cu3As2.
It would be CuF3 but this compound does not exist. Copper(II) fluoride, CuF2 exists, and K3CuF6 exists and contains copper III.