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Pb+2 C2H3O2-1 <---- these are the ions and their charges

Pb+2 C2H3O2-1 C2H3O2-1 <---- the charges have to add up to zero, so two -1 acetate ions cancel out one +2 lead ion

Pb(C2H3O2)2 <---- simplify

*** Note that acetate can either be represented by C2H3O2 or CH3COO

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