Lead IV Sulfide is PbS2
The formula for platinum (II) sulfide is PtS. The platinum (II) ion has a charge of 2+ and the sulfide ion has a charge of 2-. Therefore, in order to form a neutral compound, one platinum (II) ion combines with one sulfide ion.
Platinum (IV) Sulfide
The formula for lead (IV) chlorite is Pb(ClO2)4.
The formula is PbS. Pb is lead, and S is sulfur.
TiS for titanium sulfide (titanium(II) sulfide) and TiS2 for titanium disulfide (titanium(IV) sulfide)
Lead(II) Sulfide = PbS Lead(IV) Sulfide = PbS2
The formula of lead (II) sulphide is PbS whilst the formula of lead (IV) sulphide is PbS2. The formula is: PbS and the number of Solubility product constants is 3x10^-25 if you're interested;)
Lead has two oxidation states (+4 and +2). As a result, there are two compounds composed of lead and sulfate: lead(IV) sulfate, which is Pb(SO4)2, and lead(II) sulfate, which is PbSO4.
The chemical formula for lead (IV) sulfide is written as PbS2.
Pb (Lead) + S (Sulphur) -----> PbS (Lead Sulphide)
The formula for Lead Sulfide (or Lead Sulphide) is either: PbS for Lead(II) Sulphide, or PbS2 for Lead(IV) Sulphide.
Lead (II) sulfide would contain one atom of lead per formula unit. Actually, now that I think about it, so would lead (IV) sulfide.
Lead Sulfide is PbS.
Lead(II) is Pb2+ and sulfide is S2-, so the formula is simply PbS.
The chemical formula for tin (IV) sulfide is SnS2.The chemical formula for tin (II) sulfide is SnS.
The formula for platinum (II) sulfide is PtS. The platinum (II) ion has a charge of 2+ and the sulfide ion has a charge of 2-. Therefore, in order to form a neutral compound, one platinum (II) ion combines with one sulfide ion.
Platinum (IV) Sulfide