C2h5nh3+
C2H5NH2 is a weak base. When dissolved in water, it accepts protons (H+) to form the conjugate acid C2H5NH3+.
C2H5OH it is not an acid, it is an alchohol (ethanol).
The conjugate base of NH4+ is NH3. The formula for the conjugate base of an acid can be obtained by removing a proton (H+) from the acid molecule.
2H + + SO4 2- <-> H2SO4 Sulfuric acid is the conjugate acid here.
The conjugate acid is the acetic acid, CH3COOH.
C2H5NH2 is a weak base. When dissolved in water, it accepts protons (H+) to form the conjugate acid C2H5NH3+.
C2H5OH it is not an acid, it is an alchohol (ethanol).
The conjugate acid for this anion is HBrO, or hypobromous acid. Finding the formula of a conjugate acid is simple actually. All you have to do is remove a negative charge and ad an "H" at the beginning.
The conjugate base of NH4+ is NH3. The formula for the conjugate base of an acid can be obtained by removing a proton (H+) from the acid molecule.
2H + + SO4 2- <-> H2SO4 Sulfuric acid is the conjugate acid here.
The conjugate acid is the acetic acid, CH3COOH.
The conjugate acid of ClO2 is HClO2. This is formed by adding a proton (H+) to the ClO2 molecule, resulting in the formation of the acid.
The conjugate base of H3PO4 is H2PO4-. The formula for the conjugate base can be found by removing one proton (H+) from the acid molecule.
The conjugate acid of the sulfate ion (SO4^2-) is sulfuric acid (H2SO4). To form the conjugate acid, you add a proton (H+) to the base molecule.
The conjugate acid of the water molecule is the hydroxonium ion.
The chemical formula for ethylammonium chloride, formed by the reaction between ethylamine and hydrochloric acid, is C2H5NH3Cl.
The conjugate acid of ClO- is HClO. The conjugate acid of HClO is ClO2. The conjugate acid of HCI is H2Cl. The conjugate acid of Cl- is HCl. The conjugate acid of ClO is HClO2.