Fe (III) has a charge of 3+.
Br has a charge of 1-.
This means that in order to make the overall charge of the ionic compound of Iron III and Bromine, there must be one atom of Iron III and three atoms of Bromine.
This makes the formula FeBr3.
The answer is CaBr2. The way you get this is due to the fact that you have to balance the charges, there needs to be one negative for every positive. Ca is a +2 charge and Br is a -1 charge. Therefor we need two -1 charges to cancel out +2 charge. As you can conclude, we need 2 Bromine. CaBr2 is pronounced as Calcium Bromide.
The ionic compound for Iron is Fe3+ and the ionic compound for Bromine is Br-. So Fe3+ + Br- = FeBr3
Easy one.
Rb +
and
Br -
form the ionic compound
RbBr = Rubidium bromide
CaBr2
Yes, another example is NaCl, table salt.
Rb3P.
Like all Rb compounds it is ionic.
Its Rb because its the only metal listed and ionic compounds are formed as a result of a metal bonding with a nonmetal which is the chlorine.Rb because if you the subtract the electronegativities:(Cl) 3.2 - (Rb) .8 = 2.4 which is more than 2.0 making it ionic.
Rubidium is a group 1 metal with just one valence electron. It therefore forms the ion Rb+ as it loses the electron. The ionic formula is Rb+ Cl-
Yes, another example is NaCl, table salt.
Rb3P.
Like all Rb compounds it is ionic.
Its Rb because its the only metal listed and ionic compounds are formed as a result of a metal bonding with a nonmetal which is the chlorine.Rb because if you the subtract the electronegativities:(Cl) 3.2 - (Rb) .8 = 2.4 which is more than 2.0 making it ionic.
Rubidium is a group 1 metal with just one valence electron. It therefore forms the ion Rb+ as it loses the electron. The ionic formula is Rb+ Cl-
RbBr is the chemical formula for rubidium bromide. Rb stands for rubidium and Br for bromine.
RbBr is the chemical formula of rubidium bromide.RbBr has an ionic bond.
We know from the -ide on flouride that this compound will be an ion. So we look to cross the charges of the common ions of Rb and F Rubidium exclusively forms a 1+ ion, since it is an alkali metal, and fluorine forms a 1- ion exclusively. Therefore Rb+ + F- => RbF
Rb
Ionic bond between Rb+ cation and Cl- anion.
All the alkali and alkaline earth metals: Li, Na, K, Rb, Cs, Fr, Ra, Ba, Sr, Ca, Mg, and Be. Most other metals would also form an ionic compound with fluorine.
Generally +1 in its compounds