What is the formula for vanadium V nitride?

Answer 1

Depends on the oxidation state Vanadium is in. If it is the Vanadium (III) state you will have a [V(CN)7]4- salt such as K4[V(CN)7] which can be prepared from VCl3 and KCN in aqueous solution to form a pentagonal bi-pyramidal complex. You can then reduce this complex in liquid NH3 to form the Vanadium(II) complex K4[V(CN)6]

Answer 2

V+3 Cl-1 <---- these are the ions and their charges

V+3 Cl-1 Cl-1 Cl-1 <----- the charges have to add up to zero, so three -1 Cl ions cancels out one +3 V ion.

VCl3 <---- simplify

Answer 3

VCl5. However VCl5 cannot be prepared under normal conditions because chlorine lacks the oxidizing power to attack VCl4.

Vanadium (II) chloride (VCl2) is the most reduced vanadium chloride known. There is also Vanadium (III) chloride as Vanadium trichloride (VCl3). There is also vanadium (IV) chloride, vanadium tetrachloride (VCl4).

Now if you want to try something like vanadium and fluorine, then you can yield a result of (VF5). The increased oxidizing power of fluorine versus chlorine is going to give you what you need.

Hope this was helpful.

Answer 4

For vandium (III) nitrate it would be V(NO3)3

Answer 5

Vanadium (III) Nitrate is V(NO3)3 Vanadium (V) Nitrate is V(NO3)5

Answer 6

Formula: VN

Answer 7

V2(co3)5

Answer 8

VN5

Answer 9

Mn(CN)5