I might not know the answer to my question but I do not think it is SP^3.
The smallest radius from I Br Br I would be the bromine atom since it is closer to the central iodine atom compared to the outer iodine atom.
The element in the group of MgO, Br, LiF, and PbO is Br (Bromine).
The oxidation level of Br can vary depending on the compound it is in. In the compound HBr, the oxidation level of Br is -1. In Br2, the oxidation level of Br is 0.
Br-Cl has a more polar bond because chlorine is more electronegative than iodine, resulting in a greater difference in electronegativity between the two elements. This difference in electronegativity leads to a more polar bond in Br-Cl compared to Br-I.
Both Br and Br and H and H form non-polar covalent bonds.
The mixing of atomic orbitals is called hybridisation.
Hybridisation (biology) the process of combining different varieties of organisms to create a hybrid
carbon can have either sp3 ,sp2 or sp1 hybridised orbital depending upon the type of hybridisation hybridisation influences the bond and bond therapy (strength) in the organic compounds
its a sp3 hybridisation
u tell me
brick brim broth brat brake brawl.............. oh and br br br br br
Br-101 br-116 br-163 br-158 br-153 br-280 br-282
You do this; <br> You do this; <br> You do this; <br>
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yes
The smallest radius from I Br Br I would be the bromine atom since it is closer to the central iodine atom compared to the outer iodine atom.