sp3d
fl / fl -- Br-- fl fl fl
The central atom in BrCl3 is bromine (Br). The bromine atom in BrCl3 adopts sp3d hybridization, which involves the mixing of one 4s, three 4p, and one 4d atomic orbitals to form five sp3d hybrid orbitals.
Bromine pentafluoride is the name. The formula is BrF5
The silicon atom in SiBr4 has a hybridization state of sp3, forming four sigma bonds with the four bromine atoms. Each bond is formed by overlap between an sp3 hybrid orbital on the silicon atom and a p orbital on each bromine atom.
BrF5 has 5 single bonds formed between bromine and fluorine atoms.
In BRF5, there are 5 sigma bonds formed through sp3d hybridization by overlapping of orbitals. The fluorine atoms each donate one electron for bonding, while the bromine atom donates five electrons. This results in a trigonal bipyramidal molecular geometry around the central bromine atom.
Out of SiCl4, BrF5, AsF5, BrF3, only SiCl4 has sp3 hybridization on the central atom, which is silicon. SiCl4 has four regions of electron density around the central silicon atom, leading to sp3 hybridization. The other compounds have different geometries and hybridizations: BrF5 and AsF5 have sp3d2 hybridization, while BrF3 has sp3d hybridization.
fl / fl -- Br-- fl fl fl
The central atom in BrCl3 is bromine (Br). The bromine atom in BrCl3 adopts sp3d hybridization, which involves the mixing of one 4s, three 4p, and one 4d atomic orbitals to form five sp3d hybrid orbitals.
Bromine pentafluoride is the name. The formula is BrF5
The silicon atom in SiBr4 has a hybridization state of sp3, forming four sigma bonds with the four bromine atoms. Each bond is formed by overlap between an sp3 hybrid orbital on the silicon atom and a p orbital on each bromine atom.
BrF5 has 5 single bonds formed between bromine and fluorine atoms.
The hybridization of NBr3 is sp3, as the nitrogen atom forms four sigma bonds with the three bromine atoms. The lone pair on the nitrogen atom occupies one of the hybridized orbitals.
The nitrogen atom in NOBr has sp2 hybridization, as it forms three sigma bonds with oxygen and bromine atoms. This hybridization allows for the formation of a trigonal planar molecular geometry in NOBr.
PBr2 is also known as Phosphorous Bromide. The P is the Phosphorous element and the Br is the Bromine element. The 2 beside the Br means that there are 2 Bromine elements.... There, PBr2 is one phosphorous and 2 bromine elements. hope this helps....
sp3d2 Br hybridizes 4s, 4p and 4d If I'm not mistaken. Seems kind of strange for a hybridization since it involves two 4d orbital when you'd expect it to hybridize with only one 4d orbital, but that's what I found on a few websites.
sp3 , 2 lone pairs, 1 single bond to the oxygen, 1 double bond to oxygen