answersLogoWhite

0

The ionic compound for NaO is sodium oxide. Sodium (Na) is a metal that typically loses one electron to form a positively charged ion (Na+), while oxygen (O) is a non-metal that typically gains two electrons to form a negatively charged ion (O2-). When they combine, they form an ionic compound with the formula Na2O.

User Avatar

AnswerBot

1y ago

What else can I help you with?

Related Questions

Is NaO a ionic compound?

Yes, NaO is an ionic compound. It is composed of a metal cation (Na+) and a nonmetal anion (O2-), which form an ionic bond due to the transfer of electrons from sodium to oxygen.


Is nao ionic or covalent?

Nao is an ionic compound. It is formed by the combination of a metal (Na) with a nonmetal (O), resulting in the transfer of electrons from the metal to the nonmetal to form ions with opposite charges that are held together by ionic bonds.


Is NaCl a ionic compound or molecule?

No Its an ionic compound


Is zyban an ionic compound?

Zyban is not an ionic compound.


Is LaBr3 a covalent compound or an ionic compound?

LaBr3 is Lanthanum tribromide, and it is an ionic compound.


Is testosterone a covalent or ionic compound?

What I had found is that it is an Ionic compound


Compounds that have ionic bonds are called?

This is an ionic compound, for example a salt as potassium chloride.


Is CuS a ionic or molecular compound?

Copper(II) sulfide is an ionic compound.


What information is given by the formula of an ionic compound?

For an ionic compound, the name of the positive ion comes first, followed by the name of the negative ion. It also tells the ratio of the atoms and tells what atoms make up the compound.they describe the type and number of atoms in a molecule of the compound


What are the individual compounds in an ionic compound?

the elements which the ionic compound is constituted of


What is the chemical for the ionic compound?

An ionic compound contain a cation and an anion.


Is NI a ionic or molecular compound?

Nickel manganate is an ionic compound.