i think its 2NaOH + Cl2 ------------> NaClO + NaCl + H2O i think
The net ionic equation for the given reaction would be: H+ + OH- -> H2O
Na+ + OH- + H+ + Cl- H2O + Na+ + Cl-
The net ionic equation for the given reaction is H+ (aq) + OH- (aq) → H2O (l)
The complete ionic equation is: Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) + H2O(l) -> Na+(aq) + Cl-(aq) + H2O(l) In this reaction, the NaOH dissociates into Na+ and OH- ions, and HCl dissociates into H+ and Cl- ions. The H+ ion reacts with the OH- ion to form water, which results in the net ionic equation shown above.
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
The net ionic equation for the given reaction would be: H+ + OH- -> H2O
OH- + H+ H2O
Na+ + OH- + H+ + Cl- H2O + Na+ + Cl-
The net ionic equation for the given reaction is H+ (aq) + OH- (aq) → H2O (l)
The complete ionic equation is: Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) + H2O(l) -> Na+(aq) + Cl-(aq) + H2O(l) In this reaction, the NaOH dissociates into Na+ and OH- ions, and HCl dissociates into H+ and Cl- ions. The H+ ion reacts with the OH- ion to form water, which results in the net ionic equation shown above.
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
The balanced ionic equation for sodium chloride (NaCl) in water (H2O) is: NaCl (s) → Na+ (aq) + Cl- (aq) This equation shows the dissociation of sodium chloride into its ions sodium (Na+) and chloride (Cl-) in water.
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
The products are sodium chloride, which remains dissolved, and water. The complete ionic equation is Na+ + OH- + H+ + Cl- --> Na+ + Cl- + H2O The net ionic equation is: H+ + OH- --> H2O
Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) -> H2O(l) + Na+(aq) + Cl-(aq)
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
The net ionic equation for Na^+ + Cl^- is Na^+ + Cl^- → NaCl, which represents the formation of sodium chloride when Na^+ and Cl^- ions combine. This equation shows the reactants and products without including spectator ions that do not participate in the reaction.