What is the ionic strength of 0.01m barium chloride solution?

Answer 1

1/2 ni(cizi)2 so 1/2 (o.o1*1*2^2)+(o.o1*2*1^2)

1/2(o.o4+o.o2)

1/2*o.o6 which equals 0.03

so your ans is o.o3

Answer 2

The ionic strength of a solution can be calculated as the sum of the concentrations of all ions present in the solution squared. In this case, the barium chloride (BaCl2) solution dissociates into Ba2+ and 2Cl- ions. Since the concentration of BaCl2 is 0.01 M, the concentrations of Ba2+ and Cl- ions would be 0.01 M and 0.02 M, respectively. Therefore, the ionic strength would be (0.01)^2 + 2(0.02)^2 = 0.01.