The ionization equation for potassium sulfate (K2SO4) in water is: K2SO4 (s) -> 2K+ (aq) + SO4^2- (aq)
Write the reaction when potassium sulfide is put into water:
The first ionization energy of potassium (K) can be represented by the equation: K(g) → K+(g) + e- This equation shows that one mole of gaseous potassium forms one mole of gaseous potassium ions and one mole of electrons upon the removal of an electron.
The balanced equation for copper sulfate (CuSO4) and potassium phosphate (K3PO4) reacting is: 3CuSO4 + 2K3PO4 -> Cu3(PO4)2 + 3K2SO4
The products will be potassium sulfate and water.
The molecular equation for the reaction of potassium hydroxide (KOH) with ammonium sulfate (NH4)2SO4 is 2 KOH + (NH4)2SO4 → 2 NH4OH + K2SO4.
Write the reaction when potassium sulfide is put into water:
The first ionization energy of potassium (K) can be represented by the equation: K(g) → K+(g) + e- This equation shows that one mole of gaseous potassium forms one mole of gaseous potassium ions and one mole of electrons upon the removal of an electron.
The balanced equation for copper sulfate (CuSO4) and potassium phosphate (K3PO4) reacting is: 3CuSO4 + 2K3PO4 -> Cu3(PO4)2 + 3K2SO4
The products will be potassium sulfate and water.
The molecular equation for the reaction of potassium hydroxide (KOH) with ammonium sulfate (NH4)2SO4 is 2 KOH + (NH4)2SO4 → 2 NH4OH + K2SO4.
The balanced chemical equation for barium chloride (BaCl2) reacting with potassium sulfate (K2SO4) is: BaCl2 + K2SO4 -> BaSO4 + 2KCl. This reaction forms barium sulfate (BaSO4) and potassium chloride (KCl).
The balanced chemical equation for the reaction involving potassium hydrogen sulfate (KHSO4) and potassium hydroxide (KOH) to produce potassium sulfate (K2SO4) and water (H2O) is: 2KHSO4 + 2KOH -> K2SO4 + 2H2O
i think either potassium(II) sulfate or potassium sulfate
K2SO4 + 2NaOH ==> Na2SO4 + 2KOH
The balanced equation for potassium hydroxide (KOH) reacting with sulfuric acid (H2SO4) to form potassium sulfate (K2SO4) and water (H2O) is 2KOH + H2SO4 → K2SO4 + 2H2O.
The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4
The reaction between hydrogen sulfate (H2SO4) and potassium hydroxide (KOH) will produce potassium sulfate (K2SO4) and water (H2O) as the products. The balanced chemical equation for this reaction is: H2SO4 + 2KOH → K2SO4 + 2H2O.