What is the limiting reagent of CuI2 AlCl3 3CuCl2 AlI3?

Answer 1

The balanced reaction of cupric iodide and aluminum chloride is 3 CuI2 + 2 AlCl3 = 3 CuCl2 + 2 AlI3. This means that the limiting reaction is cupric iodide, because more of it is required than aluminum chloride.

Answer 2

CuI2 is the limiting reagent because it will be fully consumed first in the given reaction. Its moles will react with the available moles of AlCl3 to form the maximum amount of products. Any excess amounts of the other reactants will remain unreacted.

Answer 3

It would depend on the amount of each substance you have. since you didn't tell us i cannot answer your question.