This is a density problem. Density = mass/volume. As long as we know two of the variables, we can solve for the missing variable. The density of acetone is 0.791g/mL at 25ºC.
Known/Given:
volume of acetone= 28.62mL
density of acetone at 25oC = 0.791g/mL
Unknown:
mass of acetone
Formula:
density = mass/volume
Solve for mass:
density x volume = mass
0.791g/mL x 28.62mL = 22.6g
22.39g acetone has a density of 0.7857g/cm^3 which is the same as saying 0.7857g/mL/ Multiply for mass: 0.7857*28.50=22.39g (mL gets cancelled out)
Density of acetone = 0.791 gm/mL
(0.791 gm/mL) x (17.53 mL) = 13.866 grams
28,5 mL (volume) x 0,7925 g/cm3 (density) = 22,586 g (mass)
The mass is 22,72 g.
Acetone has the molecular formula of CH3COCH3 (C3H6O) and a molar mass of 58.08 g/mol.
What is the volume, In millimeter of 6.68 g of acetone ?
the answer is 6.3%
molacular mass
0.330 moles of calcium has a mass of 13.2 grams.
With a density of 0.7857g/cm3, you have a mass of 13.78mL.
Acetone has the molecular formula of CH3COCH3 (C3H6O) and a molar mass of 58.08 g/mol.
To find the volume of 10 grams of acetone, you use the fact that the density of acetone is 0.7857 grams per cubic centimeter. The density formula is given as mass divided by volume, or m/V. The volume is mass/density or 10/0.7857, which is equal to 12.73 cubic centimeter.
What is the volume, In millimeter of 6.68 g of acetone ?
The density acetone is 0.79 g/cm3. So 12 cm3 has a mass of 9.48 g
Grams are a measure of mass.
153 grams
the answer is 6.3%
80 - 75 = 5 grams.
molar mass divided by atomic mass times 6.02 x 1023 =)
This mass is 5,323 grams.
16 grams. I hope i got it right.