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If 12.5 grams of the original sample of cesium-137 remained after 90.69 years what was the mass of the original sample?
To find the original mass of the cesium-137 sample, you can use the exponential decay formula: final amount = initial amount * (1/2)^(time/half-life). With the information provided, you would have: 12.5 = initial amount * (1/2)^(90.69/30.1). Solving for the initial amount gives you approximately 40 grams.
Write the symbol of the ion with a 1 plus charge atomic number 55 and mass number 133?
The element is cesium (Cs) and the cation is Cs^1+
How many electrons does Cesium have in its outer energy level?
Cesium, or Cs, has 1 valence electron.
What is the nuclear equation for beta decay of cesium-137?
The number 87 when referred to francium is that element's atomic number. The most common isotope of francium is 223, which has a half-life of 22 minutes and decays by beta-negative emission into radium-223.
What is the oxidation number of cesium?
The oxidation number of cesium (Cs) is always +1.
If 12.5 grams of the original sample of cesium-137 remained after 90.69 years what was the mass of the original sample?
To find the original mass of the cesium-137 sample, you can use the exponential decay formula: final amount = initial amount * (1/2)^(time/half-life). With the information provided, you would have: 12.5 = initial amount * (1/2)^(90.69/30.1). Solving for the initial amount gives you approximately 40 grams.
If 1.0 mg of cesium-137 decays over a period of 90 years how many mg of cesium-137 would remain?
Since the half-life of cesium-137 is about 30 years, 3 half-lives would have passed in 90 years. The first half-life would leave .5 mg of cesium-137. The second would leave .25 mg, and the third half-life would leave .175 mg of cesium-137.
What is the mass of 5 moles of cesium?
One atom of cesium has a mass of 132.9054 amu, and one mole of cesium has a mass of 132.9054 grams, so five moles of cesium has a mass of 664.527 grams.Multiplying the mass of a particle (which can be an atom, molecule, etc.) by Avogadro's number (6.022x1023, the number of particles of a substance in 1 mole) will give you the mass of a mole of that particle, or molar mass, in grams. Avogadro's number is special because the molar mass of a substance will be the same number as its atomic mass, only in grams!
Write the symbol of the ion with a 1 plus charge atomic number 55 and mass number 133?
The element is cesium (Cs) and the cation is Cs^1+
What are the factors of 137?
The factors of 137 are 1 and 137, because it is prime.
How many unpaired electrons does Cesium have?
Cesium has 1 unpaired electron.
What is the unknown substance if it is determined that is has 55 protons 57 neutrons and 1 valence electron?
It is a Cesium isotope, with the atomic mass of 112.It could also be an ion depending on how many total electrons it has.
How many electrons does Cesium have in its outer energy level?
Cesium, or Cs, has 1 valence electron.
What is the nuclear equation for beta decay of cesium-137?
The number 87 when referred to francium is that element's atomic number. The most common isotope of francium is 223, which has a half-life of 22 minutes and decays by beta-negative emission into radium-223.
What is the chemical formula for cesium iodide?
It's CsI, because cesium has a +1 charge and iodine has a -1 charge
What is the compound formed from cesium and bromine?
The compound formed from cesium and bromine is cesium bromide, with the chemical formula CsBr. It is an ionic compound where cesium contributes a +1 charge and bromine contributes a -1 charge to form a balanced compound.
What is 137 12 as a fraction?
137 + 1/2 = (137 + 137 + 1)/2 = 275/2
