Mass and the number of mole in a given sample are related quickly with the equation #MOLE = MASS/MOLAR MASS Where the mass is in grams. Now, we know that the number of mole is one, and the molar mass can be found with any Periodic Table - 1.00794 abouts. Now, the equation reads 1 = MASS/1.00794 This can be rearranged through simple mathematics into 1*1.00794 = MASS/1.00794 * 1.00794 Or 1*1.00794 = MASS Since anything multiplied by one is itself, this can be simplified to 1.00794 = MASS So, the mass of 1 mole of Hydrogen is 1.00794 grams. Also, your question was a sentence :p
The reaction between magnesium and hydrochloric acid produces hydrogen gas according to the equation: Mg + 2HCl -> MgCl2 + H2. For every 1 mole of magnesium reacted, 1 mole of hydrogen gas is produced. Using the molar mass of hydrogen (1 g/mol), the mass of hydrogen produced would be 1 gram when 1 mole of magnesium is reacted.
The mole ratio of C5H12 to H2 in the reaction is 1:8. This means that for every 1 mole of C5H12, 8 moles of H2 are consumed or produced in the reaction.
1 gram H2 (1 mole H2/2.016 grams)(6.022 X 1023/1 mole H2) = 3 X 1023 atoms of hydrogen gas =========================
Balanced equation. Mg + H2SO4 -> MgSO4 + H2 ------------------------------------- ( sufuric acid in excess---magnesium limits, drives reaction ) 24 grams magnesium (1 mole Mg/24.31 g)(1 mole H2/1 mole Mg)(2.016 g/1 mole H2) = 1.9 grams of hydrogen gas produced ( can call it 2.0 grams ) --------------------------------------------------
The molar mass of H2 = 2.0159 g/mol
The reaction between magnesium and hydrochloric acid produces hydrogen gas according to the equation: Mg + 2HCl -> MgCl2 + H2. For every 1 mole of magnesium reacted, 1 mole of hydrogen gas is produced. Using the molar mass of hydrogen (1 g/mol), the mass of hydrogen produced would be 1 gram when 1 mole of magnesium is reacted.
The gram molecular mass of hydrogen is 1 gram per mole.
37.66 (g H2) / 2.016 (g/mol H2)= 18.68 mole H2Molar mass of hydrogen: 2.016 (g/mol H2)
The mole ratio of C5H12 to H2 in the reaction is 1:8. This means that for every 1 mole of C5H12, 8 moles of H2 are consumed or produced in the reaction.
To calculate the mass of hydrogen produced when 31.8g of zinc reacts with sulfuric acid, you need to first balance the chemical equation. The balanced equation is: Zn + H2SO4 → ZnSO4 + H2. Then, use the molar ratio from the balanced equation to convert the mass of zinc to moles, and then to moles of hydrogen. Finally, convert moles of hydrogen to mass using the molar mass of hydrogen.
The balanced chemical equation for the reaction of H2 with O2 to form H2O is: 2H2 + O2 -> 2H2O From the equation, it can be seen that 1 mole of O2 reacts with 2 moles of H2. Since the molar mass of H2 is 2 g/mol and the mass given is 2g, there is 1 mole of H2. Therefore, 1 mole of O2 is needed, which is 32g.
1 gram H2 (1 mole H2/2.016 grams)(6.022 X 1023/1 mole H2) = 3 X 1023 atoms of hydrogen gas =========================
When 1.24 L of H2 gas reacts with O2 at STP, the mole ratio between H2 and H2O is 2:2. This means that for every 1 mole of H2 gas reacting, 1 mole of water is formed. Using the ideal gas law, you can calculate the number of moles of H2 gas reacting, and then use the mole ratio to determine the number of moles of water formed. Finally, you can convert moles of water to grams using the molar mass of water.
Balanced equation first.2H2 + O2 --> 2H2OGet moles products.4 grams H2 (1 mole H2/2.016 grams) = 1.984 moles H264 grams O2 (1 mole O2/32 grams) = 2.000 moles O2I suspect hydrogen gas of limiting and driving the reaction.1.984 moles H2 (1 mole O2/2 moles H2) = 0.992 moles O2 ( you have more than this in equation )2.000 moles O2 (2 mole H2/1 mole O2) = 4.000 moles H2 ( you do not have this much and H2 will drive this reaction )1.984 moles H2 (2 moles H2O/2 moles H2)(18.016 grams/1 mole H2O)= 36 grams water produced====================
Balanced equation. Mg + H2SO4 -> MgSO4 + H2 ------------------------------------- ( sufuric acid in excess---magnesium limits, drives reaction ) 24 grams magnesium (1 mole Mg/24.31 g)(1 mole H2/1 mole Mg)(2.016 g/1 mole H2) = 1.9 grams of hydrogen gas produced ( can call it 2.0 grams ) --------------------------------------------------
The molar mass of H2 = 2.0159 g/mol
For H2 (natural occurring element Hydrogen) it is 2*1.00794 a.m.u = 2.01588 a.m.eThis means that 1.00000 mole H2 has a mass of 2.01588 grams