60.06g
The molar mass of acetic acid is 60,05 g.
The mass of one mole of a substance is its molecular mass in grams. The molecular mass of acetic acid (CH3COOH) is: 12 + (3 x 1) + 12 + 16 + 16 + 1 = 60, therefore, 1 mole of acetic acid has a mass of 60g. (The numbers used in the calculation are the mass numbers of each element)
One mole of acetic acid reacts with one mole of caustic soda (sodium hydroxide) in a neutralization reaction. The molar ratio between acetic acid and caustic soda is 1:1. Therefore, the amount of acetic acid needed to neutralize caustic soda is determined by the molarity of the caustic soda solution being neutralized.
The formula of acetic acid is NOT CHCOOH but CH3COOH which also is found back in the corrected molar mass:The total molecular mass. 12.01 gC/mol + (3 *1.008) gH/mol + 12.01 gC/mol + 2*16.00 gO/mol + 1.008 gH/mol = 60.05 grams per mole
To make Sodium Acetate, you would typically mix one mole of acetic acid (CH3COOH) with one mole of sodium hydroxide (NaOH). This will result in the formation of one mole of sodium acetate (CH3COONa) along with water. The balanced chemical equation for this reaction is CH3COOH + NaOH -> CH3COONa + H2O.
The molar mass of acetic acid is 60,05 g.
60
The mass of one mole of a substance is its molecular mass in grams. The molecular mass of acetic acid (CH3COOH) is: 12 + (3 x 1) + 12 + 16 + 16 + 1 = 60, therefore, 1 mole of acetic acid has a mass of 60g. (The numbers used in the calculation are the mass numbers of each element)
One mole of acetic acid reacts with one mole of caustic soda (sodium hydroxide) in a neutralization reaction. The molar ratio between acetic acid and caustic soda is 1:1. Therefore, the amount of acetic acid needed to neutralize caustic soda is determined by the molarity of the caustic soda solution being neutralized.
The formula of acetic acid is NOT CHCOOH but CH3COOH which also is found back in the corrected molar mass:The total molecular mass. 12.01 gC/mol + (3 *1.008) gH/mol + 12.01 gC/mol + 2*16.00 gO/mol + 1.008 gH/mol = 60.05 grams per mole
2
The chemical reaction is: One mole of aspirin plus one mole of water yields one mole of salicylic acid plus one mole of acetic acid. Aspirin=C9H8O4 Salicylic acid=C7H6O3 Acetic acid=C4H6O3
To make Sodium Acetate, you would typically mix one mole of acetic acid (CH3COOH) with one mole of sodium hydroxide (NaOH). This will result in the formation of one mole of sodium acetate (CH3COONa) along with water. The balanced chemical equation for this reaction is CH3COOH + NaOH -> CH3COONa + H2O.
The fomula for Ethanoic (Acetic) Acid is CH3COOH ; Note the use of capital letters for the elemental symbols. This is the recognised international standard. Refer to the Periodic Table for Relative Atomic Masses. C x 2 = 12 x 2 = 24 H x 4 = 1 x 4 = 4 O x 2 = 16 x 2 = 32 24 + 4 + 32 = 60 (The Mr ( Relative molcular Mass). Remember the equation Moles = mass (g) / Mr Algebraicaally rearranging mass(g) = Moles X Mr Substitute values mass(g) 1 x 60 Mass = 60 grams.
This reaction will not proceed, as the equilibrium is far to the left. In order to synthesize acetylsalicylic acid, one must use acetic anhydrate, and the reaction forms acetic acid instead of water.
One mole of sulfuric acid has a mass of approximately 98.08 grams. This corresponds to the molar mass of sulfuric acid, which is calculated by adding up the atomic masses of sulfur, oxygen, and hydrogen in one mole of the compound.
The molar mass of sulfuric acid (H2SO4) is 98.08 g/mol. Therefore, one mole of sulfuric acid would have a mass of 98.08 grams.