Your question does not make sense, an almost infinite amount of solution could be prepared if desired
25 mL
The answer is 20,15 mL.
The volume is 342 mL.
This depends on your experiment.
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
Yes, by décreasing the volume tenfold.
it is very easy to prepare working solution from a stock solution we use the formula for this purpose which is: C1V1 = C2V2 C1 is the concentration of the stock solution V1 required volume from the stock solution C2 concentration of the working solution V2 volume of the working solution
To prepare 1 M CaI aqueous solution, dissolve 29.4 g in a total volume of 100 mls, or 294 g in a total volume of 1 liter.
25 mL
To prepare 6 nM ammonium hydroxide a 30 percent solution you need to know the volume of the 30 percent solution that you have and the volume of 6nM solution you would like to make. Then use the following formula: C1V1 = C2V2 where C = concentration in moles/Liter and V = volume in liters.
The answer is 20,15 mL.
Take solution and mix different volumes with water as the final volume of all solutions is same
The volume is 342 mL.
This depends on your experiment.
i think yes by increasing volume tenfold.because 0.01 is greater than 0.1.by diluting 0.01m solution 0.1m can be prepared.
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
You need 49,8 mL H2SO4 6,4M.