The expression"molar mass" for sodium is not corresct. After today rules of IUPAc correct is atomic weight. The atomic weight of sodium is determined very exact: 22,989 769 28 (2013 data); the error is +/- 2 for the last digit of this value.
molar mass Na = 22.99g/mol (atomic weight in grams) 0.0135mol Na x (22.99g/mol) = 0.310g Na
The molar mass of NaC2H3O2.3H2O is calculated by adding the individual molar masses of its components - sodium (Na), carbon (C), hydrogen (H), oxygen (O), and water (H2O). The molar mass is found to be 136.08 g/mol.
The molar mass of sodium (Na) is 22.99 g/mol, and the molar mass of hydroxide (OH) is 17.01 g/mol. To find the molar mass of sodium hydroxide (NaOH), you can add the molar masses of sodium and hydroxide together, which equals 39.00 g/mol.
The molar mass of sodium (Na) is approximately 22.99 g/mol. To find the mass of 9 moles of sodium, you would multiply the molar mass by the number of moles: 22.99 g/mol * 9 mol = 206.91 grams. Therefore, the mass of 9 moles of sodium is approximately 206.91 grams.
The molar mass of an element corresponds to the atomic mass of the element (found on the periodic table). The atomic mass of Sodium-Na is 22.990 g, which is also the molar mass of Na. So for 1 mole of Na, there are 22.990 grams of Na. If we had 3 moles of Na, then we would simply multiply the molar mass by 3.
molar mass Na = 22.99g/mol (atomic weight in grams) 0.0135mol Na x (22.99g/mol) = 0.310g Na
To find the number of moles of Na in 15 g of NaCl, you first need to calculate the molar mass of NaCl, which is 58.44 g/mol. Since Na makes up 39.34% of the molar mass of NaCl, you can calculate the moles of Na as (15 g / 58.44 g/mol) * 0.3934 = 0.255 moles of Na.
The molar mass of sodium (Na) is 22.99 g/mol. To find the mass in grams of 0.15 moles of sodium, you can use the formula: mass = moles x molar mass. Therefore, the mass of 0.15 moles of sodium is 0.15 mol x 22.99 g/mol = 3.4485 grams.
To find the number of moles of Na in 42 grams, we can use the molar mass of Na, which is approximately 23 grams/mol. First, calculate the number of moles by dividing the given mass by the molar mass: 42 grams / 23 grams/mol = 1.83 moles of Na.
Molar mass of Na = 22.9898g/mol Molar mass of Cl = 35.45g/mol Total molar mass = 58.4398g/mol 58.4398g * 3.7mol =216.22726g
To find the mass of 3.25 moles of NaCl, first calculate the molar mass of NaCl. Sodium (Na) has a molar mass of approximately 22.99 g/mol, and chlorine (Cl) has a molar mass of about 35.45 g/mol, giving NaCl a total molar mass of about 58.44 g/mol. Therefore, the mass of 3.25 moles of NaCl is calculated as follows: 3.25 mol × 58.44 g/mol = 190.38 grams.
The molar mass of NaC2H3O2.3H2O is calculated by adding the individual molar masses of its components - sodium (Na), carbon (C), hydrogen (H), oxygen (O), and water (H2O). The molar mass is found to be 136.08 g/mol.
The molar mass of sodium (Na) is 22.99 g/mol, and the molar mass of hydroxide (OH) is 17.01 g/mol. To find the molar mass of sodium hydroxide (NaOH), you can add the molar masses of sodium and hydroxide together, which equals 39.00 g/mol.
Mass of Na = amount of Na x atomic mass = 0.71 x 23.0 = 16.3g
To find the mass of 0.893 moles of Na₂CO₃, we first calculate its molar mass. The molar mass of Na₂CO₃ (sodium carbonate) is approximately 105.99 g/mol. Therefore, the mass can be calculated using the formula: mass = moles × molar mass, which gives us 0.893 mol × 105.99 g/mol = 94.55 grams. Thus, 0.893 moles of Na₂CO₃ corresponds to approximately 94.55 grams.
The molar mass of Na2CO3 is 106 g/mol. The molar mass of sodium in Na2CO3 is 2 * 23 g/mol = 46 g/mol. To calculate the mass percent of sodium in Na2CO3, we divide the molar mass of sodium by the molar mass of Na2CO3 and multiply by 100: (46 g/mol / 106 g/mol) * 100 ≈ 43.4%.
The molar mass of sodium (Na) is approximately 22.99 g/mol. To find the mass of 9 moles of sodium, you would multiply the molar mass by the number of moles: 22.99 g/mol * 9 mol = 206.91 grams. Therefore, the mass of 9 moles of sodium is approximately 206.91 grams.