The molar mass of calcium bromide is........99,88.
To find the number of moles in 1.2 kg of calcium bromide, you first need to determine the molar mass of calcium bromide (CaBr2), which is approximately 199.89 g/mol. Then convert the mass of 1.2 kg to grams (1200 g). Finally, divide the mass in grams by the molar mass to find the number of moles. In this case, 1200g / 199.89g/mol ≈ 6 moles of calcium bromide.
That is a lot of calcium bromide we are dealing with. The formula mass of calcium bromide, CaBr2 is 40.1 + 2(79.9) = 199.9.Amount of CaBr2 = (7.4 x 1000)/199.9 = 32.0mol There are 32 moles of calcium bromide in a 7.4kg pure sample.
The molar mass of CaBr2 (calcium bromide) is calculated by adding the atomic masses of calcium (Ca) and two bromine (Br) atoms. The atomic mass of calcium is approximately 40.08 g/mol and bromine is approximately 79.90 g/mol. Therefore, the molar mass of CaBr2 is 40.08 + (2 * 79.90) = 199.88 g/mol.
The molar mass of the compound CaBr2 is 199.9 grams per mole.
The molar mass of CaSO4 is approximately 136.14 g/mol. The molar mass of calcium in CaSO4 is 40.08 g/mol. To find the percent composition of calcium in CaSO4, divide the molar mass of calcium by the molar mass of CaSO4 and multiply by 100. The percent by mass of calcium in CaSO4 is approximately 29.45%.
The molar mass of calcium bromide (CaBr2) is 199.89 g/mol. Calcium has a molar mass of 40.08 g/mol. The mass percent of calcium in calcium bromide is calculated as (40.08 g/mol / 199.89 g/mol) x 100%, which is approximately 20.04%.
To find the number of moles in 1.2 kg of calcium bromide, you first need to determine the molar mass of calcium bromide (CaBr2), which is approximately 199.89 g/mol. Then convert the mass of 1.2 kg to grams (1200 g). Finally, divide the mass in grams by the molar mass to find the number of moles. In this case, 1200g / 199.89g/mol ≈ 6 moles of calcium bromide.
That is a lot of calcium bromide we are dealing with. The formula mass of calcium bromide, CaBr2 is 40.1 + 2(79.9) = 199.9.Amount of CaBr2 = (7.4 x 1000)/199.9 = 32.0mol There are 32 moles of calcium bromide in a 7.4kg pure sample.
To calculate the mass of calcium bromide needed, you would first find the number of moles needed using the equation moles = Molarity * Volume (in liters). Then, you would use the molar mass of calcium bromide to convert moles to grams. The molar mass of calcium bromide is 199.89 g/mol.
The molar mass of CaBr2 (calcium bromide) is calculated by adding the atomic masses of calcium (Ca) and two bromine (Br) atoms. The atomic mass of calcium is approximately 40.08 g/mol and bromine is approximately 79.90 g/mol. Therefore, the molar mass of CaBr2 is 40.08 + (2 * 79.90) = 199.88 g/mol.
Sodium iodide has the highest molar mass among the compounds listed, with a molar mass of 149.89 g/mol. Sodium bromide has a molar mass of 102.89 g/mol, sodium chloride has a molar mass of 58.44 g/mol, lithium bromide has a molar mass of 86.85 g/mol, and lithium fluoride has a molar mass of 25.94 g/mol.
The molar mass of the compound CaBr2 is 199.9 grams per mole.
The molar mass of calcium acetate is approximately 142 g/mol.
The molar mass of CaSO4 is approximately 136.14 g/mol. The molar mass of calcium in CaSO4 is 40.08 g/mol. To find the percent composition of calcium in CaSO4, divide the molar mass of calcium by the molar mass of CaSO4 and multiply by 100. The percent by mass of calcium in CaSO4 is approximately 29.45%.
To find the number of moles in 3.75 grams of calcium, divide the mass of calcium by its molar mass. The molar mass of calcium is approximately 40.08 g/mol. Therefore, 3.75 grams of calcium is equal to 0.0936 moles.
Potassium bromide is KBr, so by adding together their molar masses, we get 39+80=119gmol-1
40.078