207.136
To find the moles of carbon in aluminum acetate, first calculate the molar mass of aluminum acetate (Al(CH3COO)3). The molar mass of aluminum acetate is 204.12 g/mol. The molar mass of carbon is 12 g/mol. Calculate the ratio of carbon to aluminum acetate: 12 g/mol (carbon) / 204.12 g/mol (aluminum acetate) = 0.0587 mol of carbon in 1 mol of aluminum acetate. Then, calculate the moles of carbon in 35 g of aluminum acetate: 35 g / 204.12 g/mol * 0.0587 mol = 0.01 mol of carbon.
the molar mass of cortisone acetate is about 403.2 g/mol.
The molar mass of methyl acetate (CH3COOCH3) is 74.08 g/mol.
The molar mass of ethyl acetate is approximately 88.11 g/mol.
To determine the number of moles in nickel acetate, you need to know the mass of nickel acetate. Once you know the mass, you can use the formula: moles = mass / molar mass. The molar mass of nickel acetate is 176.7 g/mol.
To find the moles of carbon in aluminum acetate, first calculate the molar mass of aluminum acetate (Al(CH3COO)3). The molar mass of aluminum acetate is 204.12 g/mol. The molar mass of carbon is 12 g/mol. Calculate the ratio of carbon to aluminum acetate: 12 g/mol (carbon) / 204.12 g/mol (aluminum acetate) = 0.0587 mol of carbon in 1 mol of aluminum acetate. Then, calculate the moles of carbon in 35 g of aluminum acetate: 35 g / 204.12 g/mol * 0.0587 mol = 0.01 mol of carbon.
the molar mass of cortisone acetate is about 403.2 g/mol.
The molar mass of calcium acetate is approximately 142 g/mol.
The molar mass of methyl acetate (CH3COOCH3) is 74.08 g/mol.
The molar mass of ethyl acetate is approximately 88.11 g/mol.
The molar mass of anhydrous aluminum chloride is 133,34 grams.
To determine the number of moles in nickel acetate, you need to know the mass of nickel acetate. Once you know the mass, you can use the formula: moles = mass / molar mass. The molar mass of nickel acetate is 176.7 g/mol.
82.03 g/mol (anhydrous)=136.08 g/mol (trihydrate)=
The molar mass aluminum chloride is 133,34 g (for the anhydrous salt).
The molar mass of aluminum chloride (AlCl3) is approximately 133.34 g/mol.
To find the concentration, you first need to calculate the molarity. First, determine the molar mass of aluminum acetate (which is 204.11 g/mol). Next, calculate the number of moles of aluminum acetate in 33.4 grams. Then divide the moles by the volume in liters (660 ml = 0.66 L) to get the molarity. The concentration of the solution is the molarity of aluminum acetate.
The exact molar mass of calcium acetate is 158.17 g/mol.