The molar mass of methane (CH₄) is approximately 16.04 g/mol.
The molar mass of methane (CH4) is approximately 16 g/mol.
To calculate the mass of four moles of methane (CH4), we first need to determine the molar mass of methane. The molar mass of CH4 is the sum of the atomic masses of carbon (12.01 g/mol) and hydrogen (1.008 g/mol) multiplied by the number of atoms in the compound. Therefore, the molar mass of CH4 is 12.01 g/mol + 4(1.008 g/mol) = 16.04 g/mol. To find the mass of four moles of methane, we multiply the molar mass by the number of moles: 16.04 g/mol x 4 mol = 64.16 grams. Therefore, four moles of methane would have a mass of 64.16 grams.
The molar mass of styrene (C8H8) is 104 g/mol. The empirical formula is CH, which has a molar mass of 13 g/mol. To find the multiplier to get the molecular formula from the empirical formula, divide the molar mass of the molecular formula by the molar mass of the empirical formula: 104 g/mol / 13 g/mol = 8. This means the multiplier is 8, and the molecular formula of styrene is C8H8.
Find out the percentage of hydrogen in the molar mass of methane. Molar mass of CH4: C = 1 * 12.01 g = 12.01 g H = 4 * 1.01 g = 4.04 g Total = 16.05 g 4.04 g/16.05 g * 100% = 25.171% 0.25171 * 20 g = 5.0342 g There are about 5.03 grams of hydrogen in 20 grams of methane gas.
To find the number of moles of methane in 8.02 g, you need to divide the given mass by the molar mass of methane (16.04 g/mol). 8.02 g / 16.04 g/mol = 0.500 moles of methane
The molar mass of methane (CH4) is approximately 16 g/mol.
The molar mass of methane (CH4) is approximately 16.04 g/mol.
To calculate the mass of four moles of methane (CH4), first determine the molar mass of methane. The molar mass of carbon (C) is approximately 12.01 g/mol, and hydrogen (H) is about 1.01 g/mol. Thus, the molar mass of CH4 is 12.01 + (4 × 1.01) = 16.05 g/mol. Therefore, the mass of four moles of methane is 4 moles × 16.05 g/mol = 64.2 grams.
The molar mass of methane (CH4) is approximately 16.04 grams per mole.
The molecular formula of the compound CH with a molar mass of 42.0 g/mol is C3H3. This can be calculated by dividing the molar mass by the molar mass of a carbon atom (12 g/mol) to determine the number of carbon atoms, and then assigning the remaining mass to hydrogen atoms.
To calculate the mass of four moles of methane (CH4), we first need to determine the molar mass of methane. The molar mass of CH4 is the sum of the atomic masses of carbon (12.01 g/mol) and hydrogen (1.008 g/mol) multiplied by the number of atoms in the compound. Therefore, the molar mass of CH4 is 12.01 g/mol + 4(1.008 g/mol) = 16.04 g/mol. To find the mass of four moles of methane, we multiply the molar mass by the number of moles: 16.04 g/mol x 4 mol = 64.16 grams. Therefore, four moles of methane would have a mass of 64.16 grams.
The molar mass of styrene (C8H8) is 104 g/mol. The empirical formula is CH, which has a molar mass of 13 g/mol. To find the multiplier to get the molecular formula from the empirical formula, divide the molar mass of the molecular formula by the molar mass of the empirical formula: 104 g/mol / 13 g/mol = 8. This means the multiplier is 8, and the molecular formula of styrene is C8H8.
Find out the percentage of hydrogen in the molar mass of methane. Molar mass of CH4: C = 1 * 12.01 g = 12.01 g H = 4 * 1.01 g = 4.04 g Total = 16.05 g 4.04 g/16.05 g * 100% = 25.171% 0.25171 * 20 g = 5.0342 g There are about 5.03 grams of hydrogen in 20 grams of methane gas.
To find the molar mass of methane (CH4), sum up the atomic masses of all the atoms in the molecule: (1 hydrogen atom x 4) + (1 carbon atom) = 4 g/mol (hydrogen) + 12 g/mol (carbon) = 16 g/mol. Therefore, the molar mass of methane (CH4) is 16 g/mol.
To find the number of moles of methane in 8.02 g, you need to divide the given mass by the molar mass of methane (16.04 g/mol). 8.02 g / 16.04 g/mol = 0.500 moles of methane
To determine the number of water molecules produced from the combustion of 13.15 g of methane (CH₄), we first write the balanced equation for the reaction: CH₄ + 2 O₂ → CO₂ + 2 H₂O. The molar mass of methane is approximately 16.04 g/mol. Therefore, 13.15 g of methane corresponds to about 0.819 moles of CH₄, which will produce 1.638 moles of water (H₂O) since each mole of methane produces 2 moles of water. Multiplying 1.638 moles by Avogadro's number (6.022 x 10²³) yields approximately 9.85 x 10²³ molecules of water.
It would be a mole of water because you find the molar mass of each compound, finding water is 18.016 g/mol and methane is 16.042 g/mol. Why? water= H2O H 2 x 1.008 O 1 x 16.000 18.016 g/mol methane= CH4 C 1 x 12.010 H 4 x 1.008 16.042 g/mol