We have 495 ml, but we need to convert this to 1000, so we divide by 495 and multiply by 1000. We also do this to 21.1g. 21.1/495*100 is 42.626g. KI's molecular weight is 166g/mol. 42.626/166 is 0.2568 molar.
To prepare a 5% potassium iodide solution, weigh 5 grams of potassium iodide and dissolve it in 100 mL of water. Stir until the potassium iodide is completely dissolved to achieve a 5% solution.
To find the number of moles of potassium iodide needed, multiply the volume of the solution (750 ml) by the molarity (1.8 moles/L). First, convert the volume to liters (750 ml = 0.75 L), then multiply 0.75 L by 1.8 moles/L to get 1.35 moles of potassium iodide.
Potassium iodide solution is a compound because it is a pure substance made up of potassium and iodine chemically bonded together in a fixed ratio.
potassium nitrate would be left was an aqueous solution and lead iodide would be the precipitate
The compound precipitate formed when potassium iodide is added to a solution of lead nitrate is lead iodide, which is a yellow precipitate. This reaction is a double displacement reaction where the potassium ion and nitrate ion switch partners to form potassium nitrate and lead iodide.
To prepare a 5% potassium iodide solution, weigh 5 grams of potassium iodide and dissolve it in 100 mL of water. Stir until the potassium iodide is completely dissolved to achieve a 5% solution.
Find moles potassium iodide first.2.41 grams KI (1 mole KI/166 grams) = 0.01452 moles KIMolarity = moles of solute/Liters of solution ( 100 ml = 0.1 Liters )Molarity = 0.01452 moles KI/0.1 Liters= 0.145 M KI solution================
The solution of potassium iodide (if it is not extremely diluted) is more dense.
To find the number of moles of potassium iodide needed, multiply the volume of the solution (750 ml) by the molarity (1.8 moles/L). First, convert the volume to liters (750 ml = 0.75 L), then multiply 0.75 L by 1.8 moles/L to get 1.35 moles of potassium iodide.
A yellow precipitate of lead iodide is formed due to the reaction between potassium iodide and lead nitrate. This reaction is a double displacement reaction, where the potassium from potassium iodide swaps places with the lead from lead nitrate, forming the insoluble lead iodide.
Potassium iodide solution is a compound because it is a pure substance made up of potassium and iodine chemically bonded together in a fixed ratio.
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
potassium nitrate would be left was an aqueous solution and lead iodide would be the precipitate
The compound precipitate formed when potassium iodide is added to a solution of lead nitrate is lead iodide, which is a yellow precipitate. This reaction is a double displacement reaction where the potassium ion and nitrate ion switch partners to form potassium nitrate and lead iodide.
Potassium iodide is used in the preparation of iodine solution to increase the solubility of iodine in water. It helps stabilize the iodine in solution by forming triiodide ions, which prevents iodine from sublimating back to a solid state. Additionally, potassium iodide helps to maintain a consistent concentration of iodine in the solution.
it is iodine and potassium iodide solution It's a orange colored solution that consists of Iodine and Potassium Iodide and is used to test a substance for starch. If the color of the solution turns black when put on/in the substance, then the substance is positive for starch.
When copper sulfate solution is mixed with potassium iodide, a solid precipitate of copper iodide is formed, while potassium sulfate remains in solution. This reaction is a double displacement reaction. The balanced chemical equation is CuSO4 + 2KI → CuI2 + K2SO4.