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Q: What is the molarity of a solution made by dissolving 125 grams of HC2H3O2 in enough water to make 1.5 L of total solution?

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what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?

The molarity of a solution made by dissolving 23,4 g of sodium sulphate in enough water to make up a 125 mL solution is 1,318.

The molarity of KNO3 is 0,058.

What is the molarity of a solution that has 50 grams of KOH dissolved in enough water to make 800 mL of solution?

Molarity=Moles of solute/Liters of solution1.350 g KOH = 0.02406 mol KOH0.02406 mol/0.2500 L =0.09624 M of KOH

Related questions

what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?

The molarity of a solution made by dissolving 23,4 g of sodium sulphate in enough water to make up a 125 mL solution is 1,318.

The molarity of KNO3 is 0,058.

What is the molarity of a solution that has 50 grams of KOH dissolved in enough water to make 800 mL of solution?

0.930 M

2.89

1.99 M

Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl

Molarity=Moles of solute/Liters of solution1.350 g KOH = 0.02406 mol KOH0.02406 mol/0.2500 L =0.09624 M of KOH

This molarity is 0,618.

Get moles sodium sulfate first.15.5 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.1091 moles Na2SO4Now,Molarity = moles of solute/ Liters of solution ( 35 ml = 0.035 Liters )Molarity = 0.1091 moles Na2SO4/0.035 Liters= 3.1 M Na2SO4 solution==================

the molarity is found by: 19.52g/770mL x 1 mole/156.7g x 1000mL/1L=0.618 mole i got 156.7g by using the chemical makeup of the solution SnF2: Sn's atomic number being 118.7 and rounding F's atomic number to 19.

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