NaBr + Ca(NO3)2 ==> is mixed in aqueous solution, nothing will precipitate out.
All salts of sodium and all nitrates are soluble. It is possible a little calcium bromide may ppt out.
The molecular equation for the reaction between sodium bromide and silver nitrate is: 2NaBr(aq) + AgNO3(aq) -> 2AgBr(s) + 2NaNO3(aq). This reaction forms solid silver bromide and aqueous sodium nitrate.
The molar mass of calcium nitrate is 164.1 g/mol. This is equivalent to 164,100 mg/mol.
The reaction between sodium bromide and silver nitrate forms silver bromide and sodium nitrate. The product is a white precipitate of silver bromide, while sodium nitrate remains dissolved in the solution as a spectator ion.
Silver bromide and sodium nitrate will react to form silver nitrate and sodium bromide as the products. The precipitate formed will be silver bromide, which is insoluble in water and will appear as a white solid in the reaction mixture.
When silver nitrate is added to a solution containing bromide ions, a white precipitate of silver bromide will form. This is due to a chemical reaction between the silver nitrate and bromide ions, resulting in the insoluble silver bromide precipitate.
The molecular equation for the reaction between sodium bromide and silver nitrate is: 2NaBr(aq) + AgNO3(aq) -> 2AgBr(s) + 2NaNO3(aq). This reaction forms solid silver bromide and aqueous sodium nitrate.
The molar mass of calcium nitrate is 164.1 g/mol. This is equivalent to 164,100 mg/mol.
It is lead bromide and potassium nitrate
Lead nitrate and potassium bromide react to form lead(II) bromide and potassium nitrate. This chemical reaction is a double displacement reaction where the cations and anions exchange partners to form the new compounds.
The reaction between sodium bromide and silver nitrate forms silver bromide and sodium nitrate. The product is a white precipitate of silver bromide, while sodium nitrate remains dissolved in the solution as a spectator ion.
Silver bromide and sodium nitrate will react to form silver nitrate and sodium bromide as the products. The precipitate formed will be silver bromide, which is insoluble in water and will appear as a white solid in the reaction mixture.
When silver nitrate is added to a solution containing bromide ions, a white precipitate of silver bromide will form. This is due to a chemical reaction between the silver nitrate and bromide ions, resulting in the insoluble silver bromide precipitate.
When ethyl bromide, an alkyl halide, reacts with alcoholic silver nitrate (AgNO3), silver bromide (AgBr) and ethanol are produced. This reaction is a substitution reaction where the bromine in ethyl bromide is replaced by the nitrate ion from silver nitrate.
The relative molecular mass of Ca(NO3)2, also known as calcium nitrate, can be calculated by adding the atomic masses of calcium (Ca), nitrogen (N), and three oxygen (O) atoms. The atomic masses are 40.08 g/mol for calcium, 14.01 g/mol for nitrogen, and 16.00 g/mol for oxygen. When you add these values together, the relative molecular mass of Ca(NO3)2 is 164.08 g/mol.
When chloride and bromide ions are mixed with silver nitrate, a white precipitate of silver chloride and a pale yellow precipitate of silver bromide are formed. This reaction is a qualitative test to distinguish between chloride, bromide, and nitrate ions.
The product of strontium bromide and silver nitrate is strontium nitrate and silver bromide. This is because there is a double displacement reaction between the two compounds where the cations and anions switch partners.
off the top of my head = 102Let's break this down. Very easy- first, take the #atoms of each element, 1 calcium,2 nitrogen, 6 oxygen. You can pull these straight off of the chemical formula. Now, multiply by molar mass- on the periodic table. (calcium) 1*40.078=40.078, (Nitrogen) 2*14.0067=28.0134, (Oxygen) 6*16=96. Now, add 'em up. 40.078+28.0134+96=164.0914 (Grams/mole)nothing to it.