I think there is no such reaction because both of the products are soluble. For one of these reactions to take place, one of the products should be a sediment or a gas.
A white precipitate of mercury(I) chloride is formed when a small amount of tin chloride SnCl2 is put into a solution of mercury(II) chloride (HgCl2); adding more SnCl2 turns this precipitate black as metallic mercury is formed.
Since mercury can be either a 1+ ion called mercury(I), or a 2+ ion called mercury(II), there are two possibilities.Formulaspotassium chloride is KClpotassium iodide is KImercury(I) chloride is HgClmercury(I) iodide is HgImercury(II) chloride is HgCl2mercury(II) iodide is HgCl2Equation with Mercury(I)KCl + HgI --> HgCl + KIEquation with Mercury(II)2KCl + HgI2 --> HgCl2 + 2KI
The word equation for this reaction is: mercury oxide (s) → mercury (l) + oxygen (g).
The reactants in the equation are mercury II oxide (HgO). This compound will decompose into mercury (Hg) and oxygen (O2) during the reaction.
The reaction between formic acid and mercuric chloride forms formyl mercury chloride and water. This reaction is a substitution reaction where the chlorine in mercuric chloride is replaced by the formate ion from formic acid.
It is: ALMGCL I think according to my periodic table. Please recommend me!
A white precipitate of mercury(I) chloride is formed when a small amount of tin chloride SnCl2 is put into a solution of mercury(II) chloride (HgCl2); adding more SnCl2 turns this precipitate black as metallic mercury is formed.
Since mercury can be either a 1+ ion called mercury(I), or a 2+ ion called mercury(II), there are two possibilities.Formulaspotassium chloride is KClpotassium iodide is KImercury(I) chloride is HgClmercury(I) iodide is HgImercury(II) chloride is HgCl2mercury(II) iodide is HgCl2Equation with Mercury(I)KCl + HgI --> HgCl + KIEquation with Mercury(II)2KCl + HgI2 --> HgCl2 + 2KI
The word equation for this reaction is: mercury oxide (s) → mercury (l) + oxygen (g).
The reactants in the equation are mercury II oxide (HgO). This compound will decompose into mercury (Hg) and oxygen (O2) during the reaction.
Cl(aq)+Ag(aq)-->AgCl(s) *do not forget to writte the charges on the elements, Cl 1 minus
The reaction between formic acid and mercuric chloride forms formyl mercury chloride and water. This reaction is a substitution reaction where the chlorine in mercuric chloride is replaced by the formate ion from formic acid.
The equation for the formation of red mercury (mercury(II) oxide) is 2Hg + O2 -> 2HgO. This reaction occurs when mercury reacts with oxygen to produce red mercury oxide.
When egg albumin is added to mercury chloride, a white precipitate called mercury albuminate is formed. This reaction occurs because the mercury chloride reacts with proteins in the egg albumin to form a complex compound. Mercury albuminate is insoluble in water and will settle out as a solid.
Mercury Nitrate: Hg(NO3)2 Sodium Chloride: NaCl
Potassium is in group one, so according to solubility rules, it will aways be soluble and therefore a spectator ion. That means that it will not take part in the chemical reaction and in a net equation it would not have to be included. HgCl2 + K2S yields HgS + 2KCl(aquious)
There are two chlorides of Mercury Mercury I chloride: Hg2Cl2 Mercury II chloride: HgCl2