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Ammonium Iodide

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Ebba Hoeger

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2y ago

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What is the compound name for NH4l?

The chemical formula NH4I is for ammonium iodide.


What is the formula for the ionic compound formed from ammonium and iodide ions?

The formula for the ionic compound formed from ammonium and iodide ions is NH4I. Ammonium ion has a charge of +1 and iodide ion has a charge of -1, so they combine in a 1:1 ratio to form a neutral compound.


Is NH4l a compound?

NH4I is a compound consisting of ammonium cations (NH4+) and iodide anions (I-). It is named ammonium iodide.


Chemical formula for ammonium iodide?

The chemical formula for ammonium iodide is NH4I.


Is NH4I soluble?

yes


What is the oxidation number for NH4I?

Oxidation numbers of the elements in NH4I are N: -3 H: +1 (4 times) I: -1 Overall: NH4+ : +1 and I- : -1


What is the formula for ammonium iodine?

The formula for ammonium iodide is NH4I. It consists of one ammonium ion (NH4+) and one iodide ion (I-).


Is NH4I a strong base?

No, NH4I is not a strong base. It is actually a salt formed from ammonium ion (NH4+) and iodide ion (I-) and does not dissociate completely in water to release hydroxide ions, which are characteristic of strong bases.


What is the formula for ammonium iodide silver nitrate?

Ammonium iodide is NH4I Silver nitrate is AgNO3


What would NH4I plus H2O equals?

When NH4I is dissolved in H2O, it will dissociate into its ions, forming NH4+ and I- ions in the solution. This reaction is considered a dissociation reaction rather than a chemical reaction where new substances are formed.


What is the name for the compound IF?

The name of this compound is iodine heptafluoride.


Is NH4OH acidic neutral or basic?

NH4I + H2O --> NH4OH + H+ + I-HI being a strong acid, remains almost wholly ionised as H+ & I- ionNH4OH being a weak base so you have some more H+ left therefore it is acidic solution. (problem: NH4OH is not an exsisting compound, most of it will react with the strong acid H+ and the remainig will be fully ionized into NH4+)Added:(problem solved: not using NH4OH as it is annon-exsisting compound)NH4I will completely dissolve in ammonium and iodide ions:NH4I --> I- + NH4+of which I- is neutral and NH4+ is quite a weak acid (pKa = 9.25). (The molar standard solution of NH4I will have pH approx. 4.6)