Potassium iodide.
Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s) PbI2 is a yellow coloured solid and will precipitate out of the solution.
The balanced symbol equation between chlorine and potassium iodide is: Cl2 + 2KI -> 2KCl + I2
The name of the formula Sb4O6 is Tetraantimony Hexoxide.
The reaction between potassium iodide (KI) and dilute sulfuric acid (H2SO4) can be represented by the following equation: 2KI + H2SO4 -> 2KHSO4 + HI
The formula name for CuI2 is copper(I) iodide.
The compound 2KI is named potassium iodide. It consists of two potassium (K) ions and one iodide (I) ion, resulting in the formula K2I. Potassium iodide is commonly used in medical applications, as well as in photography and as a dietary supplement for iodine.
2KI + Cl2 = 2KCl + I2
Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s) PbI2 is a yellow coloured solid and will precipitate out of the solution.
The balanced symbol equation between fluorine and potassium iodide is: 2KI + F2 --> 2KF + I2
The balanced symbol equation between chlorine and potassium iodide is: Cl2 + 2KI -> 2KCl + I2
you have to write... 2KI + Cl2 = 2KCl + I2
2KI + Cl2 = 2KCl + I2
2ki + h2o2 = 2koh +i2
The name of the formula changed.
The name of the formula Sb4O6 is Tetraantimony Hexoxide.
2KI + F2 ----> 2KF + I2I hope this help :) :P :D :} :]
The reaction between potassium iodide (KI) and dilute sulfuric acid (H2SO4) can be represented by the following equation: 2KI + H2SO4 -> 2KHSO4 + HI