Potassium iodide.
Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s) PbI2 is a yellow coloured solid and will precipitate out of the solution.
The balanced symbol equation between chlorine and potassium iodide is: Cl2 + 2KI -> 2KCl + I2
The name of the formula Sb4O6 is Tetraantimony Hexoxide.
The reaction between potassium iodide (KI) and dilute sulfuric acid (H2SO4) can be represented by the following equation: 2KI + H2SO4 -> 2KHSO4 + HI
The formula name for CuI2 is copper(I) iodide.
2KI + Cl2 = 2KCl + I2
Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s) PbI2 is a yellow coloured solid and will precipitate out of the solution.
The balanced symbol equation between fluorine and potassium iodide is: 2KI + F2 --> 2KF + I2
The balanced symbol equation between chlorine and potassium iodide is: Cl2 + 2KI -> 2KCl + I2
you have to write... 2KI + Cl2 = 2KCl + I2
2KI + Cl2 = 2KCl + I2
2ki + h2o2 = 2koh +i2
The name of the formula changed.
The name of the formula Sb4O6 is Tetraantimony Hexoxide.
2KI + F2 ----> 2KF + I2I hope this help :) :P :D :} :]
The reaction between potassium iodide (KI) and dilute sulfuric acid (H2SO4) can be represented by the following equation: 2KI + H2SO4 -> 2KHSO4 + HI
Diphosphorus Pentoxide is the name of the formula P2O5.