At first dissolution reaction
Molecular_equation_of_copper_II_sulfate_plus_sodium_carbonateCuSO4 + NaCO3 -------> Na2SO4 + CuCO3chebs
The chemical equation is 2Na + H2SO4 --> Na2SO4 + H2
To balance the equation, you need 2 molecules of HCN on the reactant side. This will give you the balanced equation: NaCN + H2SO4 -> Na2SO4 + 2HCN.
The balanced equation for sodium carbonate (Na2CO3) reacting with sulfuric acid (H2SO4) to form sodium sulfate (Na2SO4), water (H2O) and carbon dioxide (CO2) is: Na2CO3 + H2SO4 → Na2SO4 + H2O + CO2
The net ionic equation for the given reaction is H+ (aq) + OH- (aq) → H2O (l)
Molecular_equation_of_copper_II_sulfate_plus_sodium_carbonateCuSO4 + NaCO3 -------> Na2SO4 + CuCO3chebs
The balanced equation for CaSO4 + 2NaCl is CaCl2 + Na2SO4.
The chemical equation is 2Na + H2SO4 --> Na2SO4 + H2
To balance the equation, you need 2 molecules of HCN on the reactant side. This will give you the balanced equation: NaCN + H2SO4 -> Na2SO4 + 2HCN.
The balanced equation for sodium carbonate (Na2CO3) reacting with sulfuric acid (H2SO4) to form sodium sulfate (Na2SO4), water (H2O) and carbon dioxide (CO2) is: Na2CO3 + H2SO4 → Na2SO4 + H2O + CO2
This reaction is:Na2O + H2SO4 = Na2SO4 + H2O
The net ionic equation for the given reaction is H+ (aq) + OH- (aq) → H2O (l)
CuCl2 + Na2SO4 --> CuSO4 + 2NaCl
The balanced molecular equation is CaCl2 + Na2S -> CaS + 2NaCl. To write the ionic equation, we need to break down the reactants and products into their respective ions. This results in the ionic equation: Ca2+ + 2Cl- + 2Na+ + S2- -> CaS + 2Na+ + 2Cl-. Cross out spectator ions that appear on both sides of the equation to obtain the net ionic equation: Ca2+ + S2- -> CaS.
The balanced equation for sodium sulfate plus lithium nitrate is: 2 Na2SO4 + 3 LiNO3 -> 1 Na2(SO4)3 + 3 Li2SO4
To balance the equation CuSO4 + Na, follow these steps: Write down the unbalanced equation: CuSO4 + Na → ? Determine the products of the reaction based on the elements involved: CuSO4 + Na → Cu + Na2SO4 Now, balance the equation by ensuring that the number of atoms for each element is the same on both sides: CuSO4 + 2Na → Cu + Na2SO4
Ba2+ + [2Cl- + 2Na+] + SO42---> BaSO4 + [2Cl- + 2Na+]Ba2++ SO42- --> BaSO4