This reaction occurs in two steps.
1) Copper is oxidized by concentrated nitric acid.
3Cu + 2HNO3 = 3CuO + 2NO + H2O
2)The copper oxide is attacked by the excess HNO3:
3CuO + 6HNO3 = 3Cu(NO3)2 + 3H2O
I put 3 CuO because there are 3 parts of CuO resulting from the first reaction and so, there are 3 parts of CuO reacting with the excess acid.
Replacing the CuO with 3Cu(NO3)2 + 3H2O in the first equation, we have:
3Cu + 8HNO3 = 3Cu(NO3)2 + 2NO + 4H2O
I put 8 parts of nitric acid because there are two parts that form the oxide and six parts that form the copper nitrate.
There is also a second reaction, where NO reacts with oxygen in the air to form NO2, a very, very, very poisonous reddish-brown gas, but that's not part of the copper + nitric acid reaction
The ionic equation for the reaction between nitric acid (HNO3) and iron (Fe) is: 3H+ + Fe -> Fe3+ + 3/2H2 This equation represents the dissociation of nitric acid into H+ ions and the oxidation of iron to Fe3+ ions.
Copper reacts with nitric acid to form copper nitrate, nitrogen dioxide gas, and water. The reaction is a redox reaction where copper is oxidized and nitric acid is reduced. Be cautious when handling nitric acid as it is a strong acid and can be corrosive.
When copper nitrate reacts with sulfuric acid, copper sulfate, nitric acid, and water are produced. The balanced chemical equation for this reaction is: Cu(NO3)2 + H2SO4 → CuSO4 + 2HNO3
To determine the maximum mass of nitric acid required to react with 0.35 grams of copper metal, we need to calculate the moles of copper using its molar mass. Then, we use the balanced chemical equation between copper and nitric acid to find the mole ratio between them. Finally, we convert the moles of copper to moles of nitric acid and then to grams. The maximum mass of nitric acid needed can be determined as per the stoichiometry of the balanced chemical equation.
Copper(II) Oxide: CuO reaction with Nitric Acid: CuO + 2 HNO3 => Cu(NO3)2 + H2O Copper(I) Oxide: Cu2O reaction with Ntric Acid: Cu2O + 2HNO3 => CuNO3 + H2O
The ionic equation for the reaction between nitric acid (HNO3) and iron (Fe) is: 3H+ + Fe -> Fe3+ + 3/2H2 This equation represents the dissociation of nitric acid into H+ ions and the oxidation of iron to Fe3+ ions.
Vanadium.
Copper reacts with nitric acid to form copper nitrate, nitrogen dioxide gas, and water. The reaction is a redox reaction where copper is oxidized and nitric acid is reduced. Be cautious when handling nitric acid as it is a strong acid and can be corrosive.
When copper nitrate reacts with sulfuric acid, copper sulfate, nitric acid, and water are produced. The balanced chemical equation for this reaction is: Cu(NO3)2 + H2SO4 → CuSO4 + 2HNO3
To determine the maximum mass of nitric acid required to react with 0.35 grams of copper metal, we need to calculate the moles of copper using its molar mass. Then, we use the balanced chemical equation between copper and nitric acid to find the mole ratio between them. Finally, we convert the moles of copper to moles of nitric acid and then to grams. The maximum mass of nitric acid needed can be determined as per the stoichiometry of the balanced chemical equation.
Zn + 2H+ ----> Zn2+ + H2
Copper(II) Oxide: CuO reaction with Nitric Acid: CuO + 2 HNO3 => Cu(NO3)2 + H2O Copper(I) Oxide: Cu2O reaction with Ntric Acid: Cu2O + 2HNO3 => CuNO3 + H2O
Sulfuric acid plus copper (II) nitrate yields nitric acid plus copper (II) sulfate. Sulfuric acid plus copper (I) nitrate yields nitrous acid plus copper (I) sulfate.
There's NO reaction between AgNO3 and HNO3
Cu(s) + 4H^+(aq) + 4NO3^-(aq) ==>Cu^2+(aq) + 2NO3^-(aq) + 2NO2(g) + 2H2O(l)
When copper oxide reacts with nitric acid, it forms copper nitrate, water, and nitrogen dioxide gas. The balanced chemical equation for this reaction is CuO + 2HNO3 → Cu(NO3)2 + H2O + NO2.
When copper reacts with nitric acid, the copper is oxidized by the nitric acid to form copper(II) nitrate, nitrogen dioxide gas, and water. The reaction is a redox reaction where the copper is oxidized and the nitric acid is reduced.