This equation is simply 2 OH-1 (aq) + 2 H+1 (aq) -> 2 H2O.
The net ionic equation for the reaction between 2KOH and H2SO4 to form K2SO4 and water is: 2OH- + 2H+ -> 2H2O
The chemical equation for the reaction between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2KOH + H2SO4 → K2SO4 + 2H2O.
There is no reaction for this process.H2SO4 + NaCl => N.R.
2KHCO3(aq) + H2SO4(aq) [bidirectional arrows] K2SO4(aq) + 2CO2(g) + 2H2O(l)
Balanced equation formed: H2SO4 + 2KBr ==> 2HBr + K2SO4
The net ionic equation for the reaction between 2KOH and H2SO4 to form K2SO4 and water is: 2OH- + 2H+ -> 2H2O
Answer this question… OH- + 2H+ 2H2O(l)
The chemical equation for the reaction between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2KOH + H2SO4 → K2SO4 + 2H2O.
There is no reaction for this process.H2SO4 + NaCl => N.R.
2KHCO3(aq) + H2SO4(aq) [bidirectional arrows] K2SO4(aq) + 2CO2(g) + 2H2O(l)
Balanced equation formed: H2SO4 + 2KBr ==> 2HBr + K2SO4
H2SO4 + 2KOH = K2SO4 + 2H2O
If is K2O (potassium oxide) it would be: K2O+H2SO4=K2SO4+H2O It could also form potassium bisulfate: K2O + 2 H2SO4 = 2 KHSO4 + H2O But I'm not sure if you are referring to potassium peroxide (K2O2) or superoxide (KO2)
H2SO4 is a strong acid commonly known as sulfuric acid. NaOH is a strong base commonly known as sodium hydroxide. When the two are mixed at a ratio of 1mol of H2SO4 to 2 mols of NaOH, a neutralization reaction occurs.
The net ionic equation when potassium hydroxide and sulfuric acid are mixed is: 2K+ + 2OH- + H+ + SO4^2- -> 2H2O + K2SO4. This equation shows the key ions involved in the reaction that result in the formation of water and potassium sulfate.
The balanced chemical equation for the reaction between potassium (K) and sulfuric acid (H2SO4) to form potassium sulfate (K2SO4) and hydrogen gas (H2) is: 2K + H2SO4 -> K2SO4 + H2
2KOH + H2SO4 --> K2SO4 + 2H2O2KOH(aq) + H2SO4(aq) --> K2SO4(aq) + 2H2O(l)