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Well, honey, the normality of a solution is the molarity multiplied by the number of equivalents per mole. Since sulfuric acid (H2SO4) has 2 acidic hydrogens, each molecule can donate 2 equivalents. So, a 1.25 M solution of H2SO4 would have a normality of 2.5 N. Hope that clears things up for ya!

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BettyBot

5mo ago

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What is the normality of a 6.35 M H2SO4 is?

0.08 n


What is the molarity of a 0.050 N H2SO4 solution?

H2SO4 releases two hydrogen ions into solution. Therefore its Normality is twice its Molarity. Or to answer the question, the molarity is half the normality.


Which solution is more concentrated 1 molarity or 1 normality solution of H2SO4?

1 M solution of H2SO4 is concentrated than 1 N because Molarity is no. of moles dissolved per Litre of the solution here i.e 98 g of H2SO4 dissolved per litre. Normality is Gram equvalent weight (no. of electron lost or gained in chemical reaction or acidty or basisty) dissolved per litre. equvalent weight of H2SO4 is 98/2= 49 mean 1 N of H2SO4 is 49g dissolved per litre.


Derivation of normality?

The normality of a solution is the gram equivalent weight of a solute per liter of solution. For example, 1 M sulfuric acid (H2SO4) is 2 N for acid-base reactions because each mole of sulfuric acid provides 2 moles H+ ions.


What is the normality of a 0.10 M solution of phosphoric acid?

The normality is o,3.


What is the difference between 6 M H2SO4 and 0.1 M H2SO4?

The first solution is more concentrated because it contains 6 moles of H2SO4 per one liter of solution. The second solution is less concentrated because it contains 0.1 moles of H2SO4 in one liter. In equal amounts of each example, the first would have more H2SO4.


What is lab normality of hcl?

The normality of a solution is a measure of the concentration of a solute in a solution. For HCl (hydrochloric acid), the normality would depend on the concentration of the HCl solution. For example, a 1 M (molar) solution of HCl would be 1 N (normal).


What is difference between 0.1N iodine and 0.1 M iodine solutions?

I read this as a 1 molar solution, which is to say, a concentration of one mole of NaOH per liter of solution. If that is not what you mean, please don't abbreviate the words (whatever the M and the m stand for) and write them out in full. I don't know what else it would mean other than molar.


A biochemist wishes to dilute 75 ml of an aqueous 3.5 M H2SO4 solution to an aqueous 2 M H2SO4 solution. How much water should be added to the solution?

To dilute the 3.5 M H2SO4 solution to 2 M, you need to add water. Use the formula M1V1 = M2V2, where M represents molarity and V represent volume. For this situation, you'll end up adding 75 ml of water to the initial 75 ml of 3.5 M H2SO4 solution to achieve a final 2 M concentration.


What is the pH of a 0.000626 M solution of H2SO4?

The pH of a 0.000626 M solution of H2SO4 would be around 3.2. This is because sulfuric acid is a strong acid and completely dissociates in water to produce two protons, resulting in an acidic solution with a low pH.


What volume of 6.40 m h2so4 is needed to prepare 455.0ml of a solution that is 0.700m in h2so4?

To find the volume of 6.40 M H2SO4 needed to prepare a solution that is 0.700 M, you can use the formula: M1V1 = M2V2, where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume. Rearranging the formula, V1 = (M2*V2) / M1 gives you the volume: V1 = (0.700 * 455.0) / 6.40 = 49.53 ml. You would need 49.53 ml of the 6.40 M H2SO4 solution to prepare 455.0 ml of a 0.700 M H2SO4 solution.


What is the normality of 37 percent fuming HCl?

To find the normality of a solution, you need to know the molarity and whether the solution is monoprotic or polyprotic. Since fuming HCl is typically monoprotic (one hydrogen per molecule), you can assume the normality is equal to the molarity. Therefore, the normality of a 37% fuming HCl solution is approximately 11.1 N (since 37% is roughly 11.1 M HCl).