Alkali metals such as sodium always form univalent cations in ionic compounds, and oxygen in oxyanions is assigned an oxidation number of -2. Therefore, to achieve electrical neutrality in Na2CO3, carbon must have an oxidation number of +4.
The oxidation number of sodium (Na) in sodium carbonate (Na2CO3) is +1. The oxidation number of oxygen (O) is -2, and the oxidation number of carbon (C) is +4. Therefore, the overall compound has a charge of 0.
0. CO2 is electrically neutral. C is +4 and O is 2(-2)
The oxidation number of C in C₂O₄ is +3. Each oxygen atom carries a charge of -2, and since there are 4 oxygen atoms in total with a total charge of -8, the carbon atom's oxidation number must be +3 to balance the charges in the compound.
In KO2, O has an oxidation number of -1, K has an oxidation number of +1. In CO2, O has an oxidation number of -2, C has an oxidation number of +4. In K2CO3, O has an oxidation number of -2, C has an oxidation number of +4, and K has an oxidation number of +1. In the given reaction, the oxidation numbers for each atom remain the same as in their individual compounds.
H is +1, O is -2 overall carbon will have an oxidation # of -3
The oxidation number of sodium (Na) in sodium carbonate (Na2CO3) is +1. The oxidation number of oxygen (O) is -2, and the oxidation number of carbon (C) is +4. Therefore, the overall compound has a charge of 0.
+2 for Mg +4 for C -2 for each O
The oxidation number is + for C and -2 for O.
0. CO2 is electrically neutral. C is +4 and O is 2(-2)
The oxidation number of C in C₂O₄ is +3. Each oxygen atom carries a charge of -2, and since there are 4 oxygen atoms in total with a total charge of -8, the carbon atom's oxidation number must be +3 to balance the charges in the compound.
In KO2, O has an oxidation number of -1, K has an oxidation number of +1. In CO2, O has an oxidation number of -2, C has an oxidation number of +4. In K2CO3, O has an oxidation number of -2, C has an oxidation number of +4, and K has an oxidation number of +1. In the given reaction, the oxidation numbers for each atom remain the same as in their individual compounds.
H is +1, O is -2 overall carbon will have an oxidation # of -3
The central carbon atom has an oxidation number of -2 (O is -2, H is +1)
The oxidation number of C in FeCO3 is +4. This can be determined by assigning the oxidation number of +2 to Fe and -2 to each O atom, and then solving for C based on the overall charge of the compound.
-2 for O +4 for C
The oxidation number of carbon (C) in CH2O is +2. This is because hydrogen (H) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, so the sum of the oxidation numbers in CH2O must be zero to balance the charge.
The oxidation number of carbon in CO2 is +4, while the oxidation number of oxygen is -2.