I think it is -1
The oxidation number of the CN^- ion is -1. Carbon typically has an oxidation number of +4 and nitrogen of -3, so in the CN^- ion, carbon has a -3 oxidation number to balance the -1 overall charge.
The oxidation number of Fe in Fe(CN)6 is +2. Each CN group has a charge of -1, and since there are a total of 6 CN groups surrounding Fe, they contribute a total charge of -6. Therefore, the oxidation number of Fe must be +2 to balance the charges.
The oxidation number of nitrogen (N) in K3Fe(CN)6 is -3. This is because cyanide (CN) ion has a charge of -1 and there are three cyanide ions coordinated to one nitrogen atom in the complex ion formula.
The oxidation number of carbon in Fe(CN)6^3- is -3. To find this, you can set up the equation where the total charge of the complex ion equals the sum of the oxidation numbers of each element in the ion and solve for the unknown oxidation number.
a)3 b)2 c)1 d)4 Fe is the transitional metal K3[Fe(CN)6] , we know that Potassium, K, has an oxidation number of +1 The oxidation number of CN= -1, so 6*CN has an oxidation number of -6 so therefore Fe - 6 = -3 Fe = -3 + 6 = +3 The oxidation number of Fe is +3. so A
The oxidation number of the CN^- ion is -1. Carbon typically has an oxidation number of +4 and nitrogen of -3, so in the CN^- ion, carbon has a -3 oxidation number to balance the -1 overall charge.
The oxidation number of Fe in Fe(CN)6 is +2. Each CN group has a charge of -1, and since there are a total of 6 CN groups surrounding Fe, they contribute a total charge of -6. Therefore, the oxidation number of Fe must be +2 to balance the charges.
The oxidation number of nitrogen (N) in K3Fe(CN)6 is -3. This is because cyanide (CN) ion has a charge of -1 and there are three cyanide ions coordinated to one nitrogen atom in the complex ion formula.
The oxidation number of carbon in Fe(CN)6^3- is -3. To find this, you can set up the equation where the total charge of the complex ion equals the sum of the oxidation numbers of each element in the ion and solve for the unknown oxidation number.
a)3 b)2 c)1 d)4 Fe is the transitional metal K3[Fe(CN)6] , we know that Potassium, K, has an oxidation number of +1 The oxidation number of CN= -1, so 6*CN has an oxidation number of -6 so therefore Fe - 6 = -3 Fe = -3 + 6 = +3 The oxidation number of Fe is +3. so A
The oxidation number of Ag in Ag(CN)2- is +1. This is because the overall charge of the complex ion is -1, and each cyanide ion (CN-) has a charge of -1. Since there are two cyanide ions, the total negative charge is -2, leaving the silver ion with a +1 oxidation state to balance the charge.
CN- group has an overall charge of -1. C has oxidation of +2 and N -3 in CN since N has more negativity than C. In other words, N competes and wins with C when both try to take electrons to satisfy their need to become stable. Cheers.
in oxidation reaction addition of electron occurs.
The oxidation number of iron in sodium nitroprusside is +2. This is because the overall compound has a neutral charge, and since there are 5 cyanide ions each with a -1 charge, the iron must have a +2 oxidation state to balance the charges.
The oxidation number of the nitrogen atom in the cyanide ion (CN-) is -3. This is because carbon is more electronegative than nitrogen, so it takes the -1 oxidation state while nitrogen takes the -3 oxidation state to balance the overall charge of the ion.
Nitrogen's oxidation number is -4.Carbon's oxidation number is +3.The cyanide ion has -1 charge. Nitrogen is in -3 state. By balancing the charges: the oxidation number of carbon is +4.
Cr(CN)2