Carbonate is CO32- ion and the oxidation numbers are +4 for carbon and -2 for each oxygen.
+2 for Mg, +4 for C, -2 for each O in MgCO3
Thallium has an oxidation number of +1. Therefore, the formula for thallium carbonate would be Tl2CO3.
+3 for each Al; +4 for each C; -2 for each O
The oxidation number of carbon in carbonate (CO3^2-) is +4. In the carbonate ion, each oxygen atom has an oxidation number of -2, so the overall charge of the ion is -2. This means the oxidation number of carbon must be +4 to balance the charges in the compound.
The oxidation number of calcium in calcium carbonate (CaCO3) is +2. The oxidation number of oxygen is -2. By comparing the charges in the compound, you can deduce that the oxidation number of carbon in calcium carbonate is +4.
+2 for Mg, +4 for C, -2 for each O in MgCO3
Thallium has an oxidation number of +1. Therefore, the formula for thallium carbonate would be Tl2CO3.
Magnesium and carbonate are divalent.
+3 for each Al; +4 for each C; -2 for each O
Na2C03 Oxidation number of Na = + 1 Oxidation number of O=-2, Oxidation number of C=2x1+x+3(-2)=0 so x=4
The oxidation number of carbon in carbonate (CO3^2-) is +4. In the carbonate ion, each oxygen atom has an oxidation number of -2, so the overall charge of the ion is -2. This means the oxidation number of carbon must be +4 to balance the charges in the compound.
The oxidation number of carbonate ion (CO3) is -2. Each oxygen atom has an oxidation number of -2, and the sum of the oxidation numbers in the ion must equal the charge of the ion, which is -2.
The oxidation number of calcium in calcium carbonate (CaCO3) is +2. The oxidation number of oxygen is -2. By comparing the charges in the compound, you can deduce that the oxidation number of carbon in calcium carbonate is +4.
The oxidation number of carbon in hydrogen carbonate (HCO3-) is +4. This can be determined by considering the oxidation numbers of the other elements in the compound (hydrogen and oxygen) and applying the rule that the sum of oxidation numbers in a compound must equal zero.
The oxidation number of each copper (Cu) atom in CuCO3 is +2. The oxidation number of the oxygen (O) atoms in the carbonate ion (CO3) is -2, and the overall charge of the carbonate ion is -2.
The oxidation number of copper (Cu) in CuCO3 is +2. Oxygen typically has an oxidation number of -2, and the overall charge of the carbonate ion (CO3) is -2. Therefore, the oxidation number of copper is determined to be +2 in this compound.
The oxidation number of sodium (Na) in sodium carbonate (Na2CO3) is +1. The oxidation number of oxygen (O) is -2, and the oxidation number of carbon (C) is +4. Therefore, the overall compound has a charge of 0.