nitrogen is -3 H is plus 1
Assuming you mean NH3 since there is no N3H ....The charge on NH3 is zero; it doesn't have an oxidation number. The oxidation number of N in NH3 is 3- The oxidation number of each H in NH3 is 1+
Nitrogen is more electronegative than Hydrogen. So +1 for each hydrogen and -3 for nitrogen
The assumed oxidation number of nitrogen in ammonia (3+) in this question, is wrongly signed:The correct oxidation number if nitrogen in NITRIDES (like in ammonia NH3, ammonium NH4+ and amino groups -NH2) is minus 3, so hydrogen has oxidation value of plus 1(one, like in H+) which is in fact the only possible form when attached to nonmetals.
To calculate the oxidation number of Co(NH3)6, first identify the oxidation number of ammonia (NH3), which is -3. Since there are six ammonia molecules surrounding the cobalt (Co) atom, the total charge contributed by the ammonia ligands is -3 x 6 = -18. Since the overall charge of the complex is usually 0, the oxidation state of cobalt (Co) in this complex is +3 to balance the charge.
N has +3 state on it.Each H have -1 state.
Assuming you mean NH3 since there is no N3H ....The charge on NH3 is zero; it doesn't have an oxidation number. The oxidation number of N in NH3 is 3- The oxidation number of each H in NH3 is 1+
Nitrogen is more electronegative than Hydrogen. So +1 for each hydrogen and -3 for nitrogen
The assumed oxidation number of nitrogen in ammonia (3+) in this question, is wrongly signed:The correct oxidation number if nitrogen in NITRIDES (like in ammonia NH3, ammonium NH4+ and amino groups -NH2) is minus 3, so hydrogen has oxidation value of plus 1(one, like in H+) which is in fact the only possible form when attached to nonmetals.
To calculate the oxidation number of Co(NH3)6, first identify the oxidation number of ammonia (NH3), which is -3. Since there are six ammonia molecules surrounding the cobalt (Co) atom, the total charge contributed by the ammonia ligands is -3 x 6 = -18. Since the overall charge of the complex is usually 0, the oxidation state of cobalt (Co) in this complex is +3 to balance the charge.
N has +3 state on it.Each H have -1 state.
The oxidation state of NH3 (ammonia) is -3. Each hydrogen atom contributes a +1 oxidation state, while nitrogen has a -3 oxidation state, resulting in a neutral molecule overall.
It reacts with it. The reaction is a redx reaction. Nitrogen is reduced (its oxidation number goes from 0 to -3) and hydrogen is oxidised (its oxidation number goes from 0 to +1)
the oxidation number of nitrogen is 5
The oxidation number of nitrogen can vary depending on the compound it is in. In most cases, nitrogen has an oxidation number of -3 when it is in its elemental form or in compounds like ammonia (NH3). However, in compounds like nitrate (NO3-), nitrogen has an oxidation number of +5.
It never has -2 oxidation number. Nitrogen oxidation numbers are possible: -3 (nitrides), 0 (elemental), +3 (nitrites), +5 (nitrates). Also +1, +2 and maybe +4 are possible (in Nitro-oxides only).
Nitrogen has an oxidation number of -3. Since it is in group 15, it has 5 valence electrons. It wants to have eight, so it will gain three electrons. Electrons are negative, that's why the oxidation number is negative.
The oxidation number of zinc (Zn) in Zn(NO3)2 is +2, while in Zn(OH)4^2-, it is also +2. Therefore, there is no change in the oxidation number of zinc.