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What is the conjugate base of H3BO3?
The conjugate base of H3BO3 is B(OH)4-.
What is the oxidation number of b in the compound b4 o7?
The oxidation number of B in B4O7 is +3. This can be determined by assigning oxygen an oxidation number of -2, then setting up an equation to solve for the oxidation number of B.
What is the oxidation number of b in nabh4?
+1 for Na, +3 for B and -1 for each H The IUPAC rules would have H as +1 except when bonded to a metal. Boron is a metalloid so it would have an oxidation number on that rule would be -5. It depends what rule you have been taught.
What is the oxidation number for b2h6?
The oxidation number for boron in B2H6 is +3, and the oxidation number for hydrogen is -1. Each boron atom has an oxidation number of +3, and each hydrogen atom has an oxidation number of -1 in the B2H6 molecule.
What is the oxidation number of Na2B4O7?
In Na2B4O7, sodium (Na) has an oxidation number of +1, boron (B) has an oxidation number of +3, and oxygen (O) has an oxidation number of -2. To find the oxidation number of the whole compound, you can calculate it by adding up the oxidation numbers of each element. In this case, it would be (+1 * 2) + (+3 * 4) + (-2 * 7) = 0.
What is the conjugate base of H3BO3?
The conjugate base of H3BO3 is B(OH)4-.
What is the oxidation number of b in the compound b4 o7?
The oxidation number of B in B4O7 is +3. This can be determined by assigning oxygen an oxidation number of -2, then setting up an equation to solve for the oxidation number of B.
What is the oxidation number of b in nabh4?
+1 for Na, +3 for B and -1 for each H The IUPAC rules would have H as +1 except when bonded to a metal. Boron is a metalloid so it would have an oxidation number on that rule would be -5. It depends what rule you have been taught.
What is the oxidation number for b2h6?
The oxidation number for boron in B2H6 is +3, and the oxidation number for hydrogen is -1. Each boron atom has an oxidation number of +3, and each hydrogen atom has an oxidation number of -1 in the B2H6 molecule.
What is the oxidation number of Na2B4O7?
In Na2B4O7, sodium (Na) has an oxidation number of +1, boron (B) has an oxidation number of +3, and oxygen (O) has an oxidation number of -2. To find the oxidation number of the whole compound, you can calculate it by adding up the oxidation numbers of each element. In this case, it would be (+1 * 2) + (+3 * 4) + (-2 * 7) = 0.
How many moles are in 61.83 g H3BO3?
To find the number of moles, divide the given mass of H3BO3 by its molar mass. The molar mass of H3BO3 is calculated as (31.01) + (111) + (3*16) = 61.83 g. Therefore, 61.83 g H3BO3 is equal to 1 mole of H3BO3.
What will be the oxidation number atom B?
The oxidation number of atom B will depend on the compound or molecule it is a part of and its surrounding atoms. It is determined based on the number of valence electrons B has contributed to the compound or molecule.
Is H3BO3 soluble in water?
B(OH)3 is a covalent compound which is a weak acid.
How do you balance the chemicals of Boron and H2O?
To balance the chemical equation for Boron reacting with water (H2O), you would write it as B + 3H2O -> H3BO3 + 3/2H2, where H3BO3 represents boric acid and 3/2H2 represents hydrogen gas. This equation ensures that there is an equal number of atoms of each element on both sides of the equation.
What is the oxidation number of HClO?
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
Structure of H3BO3 reactio with CH3OH?
CH3CH2NH2 + H2O -> CH3CH2OH + NH3 Structure tends to correlate with the equation, so one would think that the central hub would be the Carbon, and everything would branch off from there
What is the oxidation number of acetate?
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
