C is +4, each oxygen is -2
The oxidation number of C in CO3-2 is 27.
+4 oxygen has an oxidation of -2, so do 3 times -2=-6, i believe Ca is a +2 and you must get the numbers to equal 0. so the answer is a +4
Oxidation number of C is +3. Oxidation number of O is -2.
+1 to each H +4 to each C -2 to each O
The oxidation number of Ca is 0 in its elemental form and is +2 in its compounds.
Oxidation number of Li is +1. It is -2 in O and +4 in C
+4 oxygen has an oxidation of -2, so do 3 times -2=-6, i believe Ca is a +2 and you must get the numbers to equal 0. so the answer is a +4
Oxidation number of C is +3. Oxidation number of O is -2.
+1 to each H +4 to each C -2 to each O
The oxidation number is + for C and -2 for O.
The oxidation number of Ca is 0 in its elemental form and is +2 in its compounds.
Oxidation number of Li is +1. It is -2 in O and +4 in C
0. CO2 is electrically neutral. C is +4 and O is 2(-2)
3+
Formaldehyde is a aldehyde. Oxidation number of C is +2.
Na2C03 Oxidation number of Na = + 1 Oxidation number of O=-2, Oxidation number of C=2x1+x+3(-2)=0 so x=4
-2 for each O, +4 for C
+2 for Fe, +4 for C, - 2 for each O