In CH2Br2, carbon has an oxidation number of -2 because hydrogen has an oxidation number of +1 and bromine has an oxidation number of -1. The sum of the oxidation numbers in a neutral compound is zero.
Oxidation number is 4, formula C3O2O=C=C=C=O
The oxidation number for carbon (C) in carbon dioxide (CO2) is +4. Each oxygen atom has an oxidation number of -2, so in the compound CO2, the total oxidation number must equal 0.
It depends on what form it is in. It can be in the 4+ oxidation state, 4- oxidation state and every oxidation state in between.
The oxidation number of C in C₂O₄ is +3. Each oxygen atom carries a charge of -2, and since there are 4 oxygen atoms in total with a total charge of -8, the carbon atom's oxidation number must be +3 to balance the charges in the compound.
-1 for Carbon (in carbide) and +2 for Ca
Oxidation number is 4, formula C3O2O=C=C=C=O
The oxidation number for carbon (C) in carbon dioxide (CO2) is +4. Each oxygen atom has an oxidation number of -2, so in the compound CO2, the total oxidation number must equal 0.
It depends on what form it is in. It can be in the 4+ oxidation state, 4- oxidation state and every oxidation state in between.
The oxidation number of C in C₂O₄ is +3. Each oxygen atom carries a charge of -2, and since there are 4 oxygen atoms in total with a total charge of -8, the carbon atom's oxidation number must be +3 to balance the charges in the compound.
-1 for Carbon (in carbide) and +2 for Ca
The oxidation number of C in FeCO3 is +4. This can be determined by assigning the oxidation number of +2 to Fe and -2 to each O atom, and then solving for C based on the overall charge of the compound.
The oxidation number of sodium (Na) is +1. The oxidation number of carbon (C) in a compound is typically +4, except in the case of CO2 where it is +4 for each oxygen (O). In oxalate (C2O4), the overall charge is -2, so the oxidation number of oxygen (O) is -2 in this compound.
In Li2Co3, lithium has an oxidation number of +1, oxygen has an oxidation number of -2, and cobalt's oxidation number can be calculated as +3 to balance the overall charge of the compound, which is zero.
The oxidation number of carbon (C) in Al4C3 is -4. This is because aluminum (Al) has an oxidation number of +3 and there are 4 aluminum atoms for a total oxidation number of +12. This must be balanced by the oxidation numbers of the carbon atoms, which must be -4 in order for the compound to be neutral.
CH2Br2 is a covalent compound. It is formed by sharing electrons between carbon (C), hydrogen (H), and bromine (Br) atoms, rather than transferring electrons as in the case of ionic compounds.
The oxidation number of C in CCl4 is +4, while the oxidation number of Cl is -1. Each Cl atom in CCl4 has an oxidation number of -1, and since there are four Cl atoms, the total negative charge from Cl is -4. The sum of the oxidation numbers in a neutral compound is zero, so the oxidation number of C must be +4 to balance the charge.
The oxidation number of Mn in MnCO3 is +2. MnCO3 is a neutral compound, so the overall sum of the oxidation numbers of all elements in the compound should equal zero. Since the oxidation number of oxygen is typically -2 and there are three oxygen atoms, the oxidation number of Mn must be +2 to balance out the charges.